graded A+
Derivative of Logs - correct answer ✔✔ y=ln g(x) --> y'=[1/g(x)] x g'(x)
ex. ln(x) = (1/x)
ln(MN) =
ln(M/N) =
ln(M^N) = - correct answer ✔✔ ln(MN) = lnM + lnN
ln(M/N) = lnM - lnN
ln(M^N) = NlnM
y' = (T/B) - correct answer ✔✔ y'= (BxT' - TxB')/(B^2)
Point Slope Form
(if ask for tangent line) - correct answer ✔✔ Y - Yp = M (X - Xp)
(Xp,Yp)
[e^g(x)]' - correct answer ✔✔ [e^g(x)]' = e^g(x) x g'(x)
(e^x)' =
(-e^x)' = - correct answer ✔✔ (e^x)' = e^x
(-e^x)' = -e^x
c bar(x)' - correct answer ✔✔ c bar(x)' = [ c(x) / x ]