Solutions – Concepts of Physics Vol 1 & 2 by HC Verma (2025) | Step-by-Step PDF

ALL 47 CHAPTERS COVERED




SOLUTIONS

, HC Verma Solutions Part 1 Chapters

Chapter 12: Simple Harmonic
Chapter 1: Introduction to Physics
Motion

Chapter 2: Physics and Mathematics Chapter 13: Fluid Mechanics

Chapter 14: Some Mechanical
Chapter 3: Rest and Motion: Kinematics
Properties of Matter

Chapter 15: Wave Motion and
Chapter 4: The Forces
Waves on a String

Chapter 5: Newton's Laws of Motion Chapter 16: Sound Waves

Chapter 6: Friction Chapter 17: Light Waves

Chapter 7: Circular Motion Chapter 18: Geometrical Optics

Chapter 8: Work and Energy Chapter 19: Optical Instruments

Chapter 9: Centre of Mass, Linear
Chapter 20: Dispersion and Spectra
Momentum, and Collision

Chapter 10: Rotational Mechanics Chapter 21: Speed of Light

Chapter 11: Gravitation Chapter 22: Photometry


Physics Volume 2: HC Verma Solutions
Explore Advanced Physics Topics in Class 12

HC Verma Solutions Part 2 Chapters

Chapter 23: Heat and Temperature Chapter 36: Permanent Magnets

Chapter 37: Magnetic Properties of
Chapter 24: Kinetic Theory of Gases
Matter

Chapter 25: Calorimetry Chapter 38: Electromagnetic Induction

Chapter 26: Laws of Thermodynamics Chapter 39: Alternating Current

,Chapter 27: Specific Heat Capacities of
Chapter 40: Electromagnetic Waves
Gases

Chapter 41: Electric Current through
Chapter 28: Heat Transfer
Gases

Chapter 42: Photoelectric Effect and
Chapter 29: Electric Field and Potential
Wave-Particle Duality

Chapter 43: Bohr's Model and Physics of
Chapter 30: Gauss's Law
Atom

Chapter 31: Capacitors Chapter 44: X Rays

Chapter 32: Electric Current in Chapter 45: Semiconductors and
Conductors Semiconductor Devices

Chapter 33: Thermal and Chemical
Chapter 46: The Nucleus
Effects of Current

Chapter 47: The Special Theory of
Chapter 34: Magnetic Field
Relativity

Chapter 35: Magnetic Field due to a
Current

, SOLUTIONS TO CONCEPTS
CHAPTER – 1
–1
1. a) Linear momentum : mv = [MLT ]
1 0 0 –1
b) Frequency : = [M L T ]
T
Force [MLT 2 ]
c) Pressure :  –1 –2
= [ML T ]
Area [L2 ]
a) Angular speed  = /t = [M L T ]
0 0 –1
2.
 M0L0 T 2
b) Angular acceleration  =   [M0L0T–2]
t T
c) Torque  = F r = [MLT ] [L] = [ML T ]
–2 2 –2
2 2 2 0
d) Moment of inertia = Mr = [M] [L ] = [ML T ]
2
MLT
3. a) Electric field E = F/q =  [MLT 3I1 ]
[IT ]
F MLT 2
b) Magnetic field B =   [MT  2I1 ]
qv [IT ][LT 1 ]
B  2a MT 2I1 ]  [L]
c) Magnetic permeability 0 =   [MLT 2I2 ]
I [I]
4. a) Electric dipole moment P = qI = [IT] × [L] = [LTI]
2 2
b) Magnetic dipole moment M = IA = [I] [L ] [L I]
5. E = h where E = energy and  = frequency.
E [ML2 T 2 ]
h=  1
[ML2 T 1 ]
 [T ]
Q [ML2 T 2 ]
6. a) Specific heat capacity = C =   [L2 T 2K 1 ]
mT [M][K ]
L  L2 [L]
b) Coefficient of linear expansion =  = 1   [K 1 ]
L 0 T [L ][R]
PV [ML1T 2 ][L3 ]
c) Gas constant = R =   [ML2 T 2K 1(mol) 1 ] 
nT [(mol )][K ]
7. Taking force, length and time as fundamental quantity
m ( force/acce leration) [F / LT 2 ] F
a) Density =   2
 4 2  [FL 4 T 2 ]
V Volume [L ] LT
2 –2
b) Pressure = F/A = F/L = [FL ]
–2 –1
c) Momentum = mv (Force / acceleration) × Velocity = [F / LT ] × [LT ] = [FT]
1 Force
d) Energy = mv 2   ( velocity )2
2 accelerati on
 F   F 
=  2   [LT 1 ]2    2   [L2 T  2 ]  [FL]
 LT   LT ] 
metre
= 36  10 cm/min
5 2
8. g = 10 2
sec
9. The average speed of a snail is 0.02 mile/hr
0.02  1.6  1000 –1
Converting to S.I. units, m/sec [1 mile = 1.6 km = 1600 m] = 0.0089 ms
3600
The average speed of leopard = 70 miles/hr
70  1.6  1000
In SI units = 70 miles/hour = = 31 m/s
3600

1.1