AV Math- cts-I Professional AV Systems Installation
Exam
1. 36.7 inches
A mounted 1.78:1 display in a room has a diagonal
mea- surement of 42 inches (1067 mm) and a
(Multiply the height of the
height of 20.6 inches (523 mm). What is the width
display by the width of the
of the display?
aspect ratio.W= H x AR W=
20.6 x 1.78 W= 36.668
W= 36.7 inches)
2. 4:3 A company requires a 1:33.1 screen to be installed
in a room. The existing projector in the room is
configured to
(1.33:1 is the same as 4:3 AR = 4:3) project an image that is 44.3 in. high & 59 in.
What is aspect
ratio of the projected image?
3. 294.2; 337.5 aspect ra- tio of the screen
Substitute W, 120 in
(To find the width, multiply Substitute H, 90 in
the aspect ratio width & the Step 2: CalculateAR = 120/90
screen height. W= AR= 1.33)
1.78*165.3 W=294.234
or 294.2 inTo find the
diagonal, use Pythagoren
theorem and then the square
root of answer 165.3
2 +294.234 2 = 27618.324
square
root =337.48 or 337.5
inches)
4. 1.33
(Step 1: Determine the
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3
Exam
1. 36.7 inches
A mounted 1.78:1 display in a room has a diagonal
mea- surement of 42 inches (1067 mm) and a
(Multiply the height of the
height of 20.6 inches (523 mm). What is the width
display by the width of the
of the display?
aspect ratio.W= H x AR W=
20.6 x 1.78 W= 36.668
W= 36.7 inches)
2. 4:3 A company requires a 1:33.1 screen to be installed
in a room. The existing projector in the room is
configured to
(1.33:1 is the same as 4:3 AR = 4:3) project an image that is 44.3 in. high & 59 in.
What is aspect
ratio of the projected image?
3. 294.2; 337.5 aspect ra- tio of the screen
Substitute W, 120 in
(To find the width, multiply Substitute H, 90 in
the aspect ratio width & the Step 2: CalculateAR = 120/90
screen height. W= AR= 1.33)
1.78*165.3 W=294.234
or 294.2 inTo find the
diagonal, use Pythagoren
theorem and then the square
root of answer 165.3
2 +294.234 2 = 27618.324
square
root =337.48 or 337.5
inches)
4. 1.33
(Step 1: Determine the
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3
