M4: Exam - Requires Respondus LockDown
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Due No due date
Points 100
Questions 10
Time Limit 120 Minutes
Requires Respondus LockDown Browser
Attempt History
Attempt Time Score
LATEST Attempt 1 42 minutes 89 out of 100
Score for this quiz: 89 out of 100
Submitted Jan 21 at 4:11am
This attempt took 42 minutes.
1
You may find the following resources helpful:
Scientific Calculator (Links to an external site.)
Periodic Table
Equation Table
, Show the determination of the charge on the ion formed by the Ga31 atom.
Your Answer:
1s 2s 2p 3s 3p 4s 3d 4p3
metal lose electrons
lost of 3 electrons
Ga31 +3
Ga31 (metal = lose electrons) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p1
lose 3e → Ga+3
2
You may find the following resources helpful:
Scientific Calculator (Links to an external site.)
Periodic Table
Equation Table
The entire question should be changed to the following for every version:
H = 2.1 I = 2.7
Li = 1.0 Be = 1.5 B = 2.0 C = 2.5 N = 3.0 O= 3.5 F = 4.0
Na = 1.0 Mg = 1.2 Al = 1.5 Si = 1.8 P = 2.1 S = 2.5 Cl = 3.0
K = 0.8 Ca = 1.0 Ga = 1.6 Ge = 1.8 As = 2.0 Se = 2.4 Br = 2.8
Using the electronegativities from the table above, show the determination of the
polarity of each different type of bond in the following molecule
Your Answer:
h-o = 3.5-2.1=1.4 polar
n-o = 3.5-3.0=.5 polar
Browser + Webcam
Due No due date
Points 100
Questions 10
Time Limit 120 Minutes
Requires Respondus LockDown Browser
Attempt History
Attempt Time Score
LATEST Attempt 1 42 minutes 89 out of 100
Score for this quiz: 89 out of 100
Submitted Jan 21 at 4:11am
This attempt took 42 minutes.
1
You may find the following resources helpful:
Scientific Calculator (Links to an external site.)
Periodic Table
Equation Table
, Show the determination of the charge on the ion formed by the Ga31 atom.
Your Answer:
1s 2s 2p 3s 3p 4s 3d 4p3
metal lose electrons
lost of 3 electrons
Ga31 +3
Ga31 (metal = lose electrons) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p1
lose 3e → Ga+3
2
You may find the following resources helpful:
Scientific Calculator (Links to an external site.)
Periodic Table
Equation Table
The entire question should be changed to the following for every version:
H = 2.1 I = 2.7
Li = 1.0 Be = 1.5 B = 2.0 C = 2.5 N = 3.0 O= 3.5 F = 4.0
Na = 1.0 Mg = 1.2 Al = 1.5 Si = 1.8 P = 2.1 S = 2.5 Cl = 3.0
K = 0.8 Ca = 1.0 Ga = 1.6 Ge = 1.8 As = 2.0 Se = 2.4 Br = 2.8
Using the electronegativities from the table above, show the determination of the
polarity of each different type of bond in the following molecule
Your Answer:
h-o = 3.5-2.1=1.4 polar
n-o = 3.5-3.0=.5 polar
