MIP1501
Assignment 3
Due 30 July 2025
, Mathematics For Intermediate Phase Teachers I (MIP1501)
ASSIGNMENT 03
UNIQUE NUMBER – 178273
Closing date: 30 July 2025
QUESTION 1 [31 MARKS]
1.1.1
A tractor travels 90 km using 18 litres of fuel.
To find how much fuel is needed for 130 km:
→ Set up a proportion:
90 km : 18 litres = 130 km : x litres
x = (18 × 130) / 90 = 26 litres
Answer: 26.00 litres
1.2
7 kg tomatoes = R56.63
10 kg tomatoes = (56.63 ÷ 7) × 10 = R80.90
Answer: R80.90
1.3
30 men = 20 days
Let x be number of days for 25 men.
More men → less time.
→ 30 × 20 = 25 × x
→ x = (30 × 20) / 25 = 24 days
Answer: 24 days
1.4.1
Chicken price: R19 per 200 g = R95 per kg
(1 kg = 1000 g → 1000/200 = 5 × R19)
Answer: R95.00
Assignment 3
Due 30 July 2025
, Mathematics For Intermediate Phase Teachers I (MIP1501)
ASSIGNMENT 03
UNIQUE NUMBER – 178273
Closing date: 30 July 2025
QUESTION 1 [31 MARKS]
1.1.1
A tractor travels 90 km using 18 litres of fuel.
To find how much fuel is needed for 130 km:
→ Set up a proportion:
90 km : 18 litres = 130 km : x litres
x = (18 × 130) / 90 = 26 litres
Answer: 26.00 litres
1.2
7 kg tomatoes = R56.63
10 kg tomatoes = (56.63 ÷ 7) × 10 = R80.90
Answer: R80.90
1.3
30 men = 20 days
Let x be number of days for 25 men.
More men → less time.
→ 30 × 20 = 25 × x
→ x = (30 × 20) / 25 = 24 days
Answer: 24 days
1.4.1
Chicken price: R19 per 200 g = R95 per kg
(1 kg = 1000 g → 1000/200 = 5 × R19)
Answer: R95.00
