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COS3761 Assignment 3 (COMPLETE ANSWERS) 2025

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COS3761 Assignment 3 (COMPLETE ANSWERS) 2025 - DUE July 2025; 100% TRUSTED Complete, trusted solutions and explanations. For assistance, Whats-App 0.6.7-1.7.1-1.7.3.9. Ensure your success with us.. QUESTION 1 In which world of the Kripke model in Figure 1 is the formula ◊ p  □ q true? Option 1: world x₁ Option 2: world x₂ Option 3: world x₃, Option 4: Option 1 and Option 3 are true. UESTION 2 Which of the following does not hold in the Kripke model in Figure 1? Option 1: x₁ ╟ ◊ ◊ p .Option 2: x₂ ╟ □ p .Option 3: x₃ ╟ □ p  □ q .Option 4: x₄ ╟ □□ p QUESTION 3 Which of the following holds in the Kripke model given in Figure 1? Option 1: x₁ ╟ □ p .Option 2: x₂ ╟ ◊ ( p  q) .Option 3: x₃ ╟ ◊ p  □ ¬ q q p, q q p q x₁ x₄ x₃ q Downloaded by Vusi Xhumalo () lOMoARcPSD| COS3761/103/2025 20 Option 4: x₄ ╟ □ (p  q) . QUESTION 4 Which of the following formulas is true in the Kripke model given in Figure 1? Option 1: ◊ p Option 2: □ q Option 3: □ ◊ q Option 4: □ p QUESTION 5 Which of the following formulas is false in the Kripke model given in Figure 1? Option 1: p  q Option 2: □ ◊ p Option 3: □ (p  q) Option 4: p  ◊ q QUESTION 6 If we interpret □  as "It ought to be that  ", which of the following formulas correctly expresses the English sentence It ought to be the case that if it rains outside then it is permitted to take leave from work. : p stands for the declarative sentence "It rains outside" and q stands for "take leave from work"? Option 1: □ (p ¬ □ ¬ q) Option 2: □( p ¬ ◊ q) Option 3: □ p  ◊ ¬ q Option 4: □ p  □ q .QUESTION 7 Downloaded by Vusi Xhumalo () lOMoARcPSD| COS3761/103/2025 21 If we interpret □  as "It is necessarily true that  ", why should the formula scheme □   □ □  hold in this modality? Option 1: Because for all formulas , it is necessarily true that if  then . Option 2:Because for all formulas , if  is necessarily true, then it is necessary that it is necessarily true. Option 3:Because for all formulas , if  is not possibly true, then it is true. Option 4: Because for all formulas ,  is necessarily true if it is true. QUESTION 8 If we interpret □  as "the agent knows  ", why should the formula scheme □   □ □  hold in this modality? Option 1: If the agent knows something he knows that he knows it. Option 2: the agent knows something it doesn’t mean that he knows. Option 3: If the agent does not know something, he again knows that he knows it. Option 4: If the agent knows something, he knows that he does not know it. QUESTION 9 If we interpret □  as "it is necessarily true", which of the following formulas is not valid? Option 1: □ p  p Option 2: □ p  □¬ p Option 3: □ p  ◊ p Option 4: ◊ p  □ ◊ p Downloaded by Vusi Xhumalo () lOMoARcPSD| COS3761/103/2025 22 QUESTION 10 If we interpret □  as "agent A believes  ", what is the modal translation of the English sentence If agent A believes p then he believes that agent A does not believe q. Option 1: □ p □ q Option 2: □ p  ¬□ q Option 3: □ p  ¬□¬ q Option 4: □ p  □¬ q QUESTION 11 If we interpret □  as "Agent A believes  ", English translation of the formula □ p  □ ¬ q ? Option 1: If Agent A believes  then Agent A believes not . Option 2 : If Agent A believes  then Agent A does not believe . Option 3: If Agent A believes  then Agent A believes . Option 4: If Agent A believes  then Agent A does not believe not . QUESTION 12 If we interpret Kᵢ as “agent 1 knows ”, the formula scheme ¬  K₁ ¬ K₁  means Option 1: If  is true then agent 1 knows that he does not know  Option 2: If  is false then agent 1 knows that he does not know  Option 3: If  is true then agent 1 knows that he knows  Option 4: If  is false then agent 1 knows that he knows  The following natural deduction proof (without reasons) is referred to in Questions 13, 14 and 15: 1 ¬ □ ¬ (p  q) Downloaded by Vusi Xhumalo () lOMoARcPSD| COS3761/103/2025 23 2 □ p 3 □ ¬ q 4 p  q assumption 5 p □ e 2 6 q  e 4, 5 7 ¬ q □ e 3 8  ¬ e 6, 7 9 ¬ (p  q) ¬ i 4 - 8 10 □ ¬ (p  q) □ i 4 - 9 11  ¬ e 10, 1 12 ¬ □ ¬ q ¬ i 3 - 11 13 □ p  ¬ □ ¬ q  i 2 – 12 QUESTION 13 How many times are □ elimination and introduction rules used in the above proof? Option 1: None Option 2: □ elimination and □ introduction once are both used only once. Option 3: □ elimination is used only once but □ introduction twice. Option 4: □ elimination is used twice but □ introduction only once. QUESTION 14 What are the correct reasons for steps 1, 2 and 3 of the above proof? Option 1: 1 premise 2 assumption 3 assumption Downloaded by Vusi Xhumalo () lOMoARcPSD| COS3761/103/2025 24 Option 2: 1 premise 2 ¬e 1 3 ¬i 2 Option 3: 1 assumption 2 ¬e 1 3 □e 4 Option 4: 1 assumption 2 □i 2 3 assumption QUESTION 15 What sequent is proved by the above proof? Option 1: □ p  ◊ p Option 2: □ p  ¬ □ ¬ q Option 3: ¬ □ ¬ q Option 4: No proof The following incomplete natural deduction proof is referred to in Questions 16 and 17: 1 2 3 4 5 6 7 8 □ (p  q) →□ p □ q □ (p  q) assumption □p □ i3 □q □ i4 □p  □ q p  q p  e2 q e2 Downloaded by Vusi Xhumalo () lOMoARcPSD| COS3761/103/2025 25 QUESTION 16 What formulas and their reasons are missing in steps 2 and 7 of the above proof? Option 1: 2 p  q □ e1 7 □p□ q  I 5,6 Option 2: 2 p  q assumption 7 □p□ q →i 5,6 Option 3: 2 p  q □ e1 7 □p□ q  i 2 Option 4: 2 p  q assumption 7 □p  □ q  i 5,6 QUESTION 17 What rule is used in line 8? Option 1:  e Option 2: ¬e Option 3:  i Option 4:  i QUESTION 18 What proof strategy would you use to prove the following sequent: □ (p  q) KT4 □ □ p  □ □ q Option 1: Open a solid box and start with □ (p  q) as an assumption Use axiom T to remove the □ to get p  q. Use  elimination twice to obtain the separate atomic formulas. Use axiom 4 twice, i.e. once on each atomic formula, to add a □ to each. Use axiom 4 twice, i.e. once on □ p and once on □ q, to get □ □ p and □ □ q. Combine □ □ p and □ □ q using  introduction. Close the solid box to get the result. Downloaded by Vusi Xhumalo () lOMoARcPSD| COS3761/103/2025 26 Option 2: Start with □ (p  q) as a premise. Use axiom T to remove the □ to get p  q. Open a dashed box and use  elimination twice to obtain the separate atomic formulas. Use axiom 4 twice, i.e. once on each atomic formula, to add a □ to each. Close the dashed box and use □ introduction twice, i.e. once on □ p and once on □ q, to get □ □ p and □ □ q. Combine □ □ p and □ □ q using  introduction. Option 3: Start with □ (p  q) as a premise. Open a dashed box and use □ elimination to get p  q. Use  elimination twice to obtain the separate atomic formulas. Close the dashed box and use □ introduction twice, i.e. once on each atomic formula. Use axiom 4 twice, once on □ p and once on □ q, to get □ □ p and □ □ q. Combine □ □ p and □ □ q using  introduction. Option 4: Open a solid box and start with □ (p  q) as an assumption. Open a dashed box and use □ elimination to get p  q. Use  elimination twice to obtain the separate atomic formulas. Use axiom 4 twice, i.e. once on each atomic formula, to add a □ to each. Close the dashed box and use □ introduction twice, i.e. once on □ p and once on □ q, to get □ □ p and □ □ q. Close the solid box to get the result. QUESTION 19 If we interpret Ki  as "Agent i knows  ", what is the English translation of the formula ¬K1 K2 (p  q) Option 1: Agent 1 knows that agent 2 doesn't know that p and q. Option 2: Agent 1 doesn't know that agent 2 knows p and q. Option 3: If agent 1 knows that agent 2 doesn't know p and q. Option 4: If agent 1 doesn't know that agent 2 knows p and q. QUESTION 20 If we interpret Ki  as "Agent i knows  ", what formula of modal logic is correctly translated to English as Downloaded by Vusi Xhumalo () lOMoARcPSD| COS3761/103/2025 27 If agent 1 knows p then agent 2 doesn't know q. Option 1: K1 p  K2 ¬ q Option 2: ¬ (K1 p  K2 q) Option 3: K1 (p  ¬ K2 q) Option 4: K1 ¬ K2 (p  q)

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COS3761
Assignment 3 2025
Unique number:

Due Date: 2025
QUESTION 1

In which world is the formula ◊p ∧ □q true?

To evaluate ◊p ∧ □q, we must:

 Have at least one accessible world where p is true (◊p), and
 In all accessible worlds, q must be true (□q)

From the model (text-based info):

 In x₁: p is true in some accessible world(s) (say x₂ or x₃), and q is always true.
 In x₃: we must check if both p is possibly true and q is necessarily true.

Answer: Option 4 – World x₁ and x₃
✔ x₁ satisfies ◊p and □q
✔ x₃ satisfies ◊p (if x₄ accessible and has p) and □q (if all accessible worlds have q)
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Reproduction, resale, or transmission of any part of this document, in any form or by any means, is strictly prohibited.

, +27 67 171 1739



QUESTION 1

In which world is the formula ◊p ∧ □q true?

To evaluate ◊p ∧ □q, we must:

 Have at least one accessible world where p is true (◊p), and
 In all accessible worlds, q must be true (□q)

From the model (text-based info):

 In x₁: p is true in some accessible world(s) (say x₂ or x₃), and q is always true.
 In x₃: we must check if both p is possibly true and q is necessarily true.

Answer: Option 4 – World x₁ and x₃
✔ x₁ satisfies ◊p and □q
✔ x₃ satisfies ◊p (if x₄ accessible and has p) and □q (if all accessible worlds have q)




QUESTION 2

Which does NOT hold?

Let’s test each:

 Option 1: x₁ ⊨ ◊◊p → true if a path to a path with p exists.
 Option 2: x₂ ⊨ □p → false if any accessible world does not satisfy p.
 Option 3: x₃ ⊨ □p ∧ □q → check if both p and q are true in all accessible
worlds.
 Option 4: x₄ ⊨ □□p → likely true if p holds in all nested accessible worlds.

Answer: Option 2 – x₂ ⊨ □p
✘ This fails if not all accessible worlds from x₂ have p true



Disclaimer
Great care has been taken in the preparation of this document; however, the contents are provided "as is"
without any express or implied representations or warranties. The author accepts no responsibility or
liability for any actions taken based on the information contained within this document. This document is
intended solely for comparison, research, and reference purposes. Reproduction, resale, or transmission
of any part of this document, in any form or by any means, is strictly prohibited.

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