MAT2611
ASSIGNMENT 9 2025
DUE: 8 AUGUST 2025
, MAT2611
ASSIGNMENT 09
Due date: Thursday, 8 August 2025
1 = ( 2; 3) and v2
Problem 1. Consider the basis S = fv1 ; v2 g for R2 ; where v = ( 1; 0).
Let T : R2 ! R3 be the linear transformation such that
2
T (v1 ) = (2; 3; 1) and T (v ) = (1; 2; 4) :
Find a formula for T (x; y) ; and use that formula to …nd T (2; 3).
Problem 1
We are given a basis S = {v1 , v2 } for R2 , where:
v1 = (−2, 3),
v2 = (−1, 0)
and a linear transformation T : R2 → R3 such that:
T (v1 ) = (2, 3, 1),
T (v2 ) = (1, 2, 4)
Step 1: Express (x, y) as a linear combination of v1 , v2
Let:
(x, y) = av1 + bv2 = a(−2, 3) + b(−1, 0) = (−2a − b, 3a)
So we solve:
−2a − b = x and 3a = y
y
From the second equation: a = 3
Substitute into the first:
y 2y
−2 ( ) − b = x ⇒ b = −x −
3 3
Step 2: Use linearity of T
T (x, y) = a ⋅ T (v1 ) + b ⋅ T (v2 )
y 2y
= (2, 3, 1) + (−x − ) (1, 2, 4)
3 3
ASSIGNMENT 9 2025
DUE: 8 AUGUST 2025
, MAT2611
ASSIGNMENT 09
Due date: Thursday, 8 August 2025
1 = ( 2; 3) and v2
Problem 1. Consider the basis S = fv1 ; v2 g for R2 ; where v = ( 1; 0).
Let T : R2 ! R3 be the linear transformation such that
2
T (v1 ) = (2; 3; 1) and T (v ) = (1; 2; 4) :
Find a formula for T (x; y) ; and use that formula to …nd T (2; 3).
Problem 1
We are given a basis S = {v1 , v2 } for R2 , where:
v1 = (−2, 3),
v2 = (−1, 0)
and a linear transformation T : R2 → R3 such that:
T (v1 ) = (2, 3, 1),
T (v2 ) = (1, 2, 4)
Step 1: Express (x, y) as a linear combination of v1 , v2
Let:
(x, y) = av1 + bv2 = a(−2, 3) + b(−1, 0) = (−2a − b, 3a)
So we solve:
−2a − b = x and 3a = y
y
From the second equation: a = 3
Substitute into the first:
y 2y
−2 ( ) − b = x ⇒ b = −x −
3 3
Step 2: Use linearity of T
T (x, y) = a ⋅ T (v1 ) + b ⋅ T (v2 )
y 2y
= (2, 3, 1) + (−x − ) (1, 2, 4)
3 3