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Exam (elaborations)

Algebra and Trigonometry 7th Edition - Solutions Manual by Robert F. Blitzer

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This comprehensive solutions manual for Algebra and Trigonometry, 7th Edition by Robert F. Blitzer provides fully worked-out solutions to all odd-numbered exercises and selected chapter review problems. Structured to match the textbook’s layout, it covers a wide range of topics including real numbers, algebraic expressions, equations and inequalities, functions and graphs, polynomial and rational functions, exponential and logarithmic functions, trigonometric identities and equations, systems of equations, matrices, sequences and series, and conic sections. Each solution is presented with step-by-step reasoning, supporting student learning, exam preparation, and homework accuracy. Ideal for reinforcing classroom instruction and for self-paced study, this manual is a valuable resource for mastering algebra and trigonometry concepts.

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Institution
Algebra And Trigonometry, 7th Edition
Course
Algebra and Trigonometry, 7th edition











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Institution
Algebra and Trigonometry, 7th edition
Course
Algebra and Trigonometry, 7th edition

Document information

Uploaded on
July 4, 2025
Number of pages
1600
Written in
2024/2025
Type
Exam (elaborations)
Contains
Questions & answers

Content preview



INSTRUCTOR’S
SOLUTIONS MANUAL
ST

DANIEL S. MILLER
Niagara County Community College
U
VI

ALGEBRA AND TRIGONOMETRY
A

SEVENTH EDITION
_A
PP
RO
Robert Blitzer
Miami Dade College
VE
D
?

, TABLE OF CONTENTS for INSTRUCTOR SOLUTIONS

ALGEBRA AND TRIGONOMETRY 7E
ST

Chapter P Fundamental Concepts of Algebra ............................................................................. 1
Chapter 1 Equations and Inequalities ........................................................................................ 75
U
Chapter 2 Functions and Graphs ............................................................................................. 215
Chapter 3 Polynomial and Rational Functions ........................................................................ 359
VI
Chapter 4 Exponential and Logarithmic Functions ................................................................. 515
Chapter 5 Trigonometric Functions ........................................................................................ 593
A
Chapter 6 Analytic Trigonometry ........................................................................................... 835
Chapter 7 Additional Topics in Trigonometry ........................................................................ 969
_A
Chapter 8 Systems of Equations and Inequalities ................................................................. 1117
Chapter 9 Matrices and Determinants ................................................................................... 1259
Chapter 10 Conic Sections and Analytic Geometry ................................................................ 1377
PP
Chapter 11 Sequences, Induction, and Probability.................................................................. 1497
RO
VE
D
?

iii

, Chapter P
Fundamental Concepts of Algebra

Section P.1 6. a. 1− 2
Check Point Exercises Because 2 ≈ 1.4, the number inside the
ST
absolute value bars is negative. The absolute
1. 8 + 6( x − 3)2 = 8 + 6(13 − 3)2 value of x when x < 0 is –x. Thus,
= 8 + 6(10) 2 (
1 − 2 = − 1 − 2 = 2 −1 )
= 8 + 6(100)
= 8 + 600 π −3
U
b.
= 608 Because π ≈ 3.14, the number inside the
absolute value bars is positive. The absolute
2. a. Since 2016 is 16 years after 2000, substitute 16 value of a positive number is the number itself.
VI
for x. Thus,
T = − x 2 + 361x + 3193 π − 3 = π − 3.
= −(16) 2 + 361(16) + 3193
= 8713 x
c.
A
The average cost of tuition and fees at public x
U.S. colleges for the school year ending in Because x > 0, x = x.
2016 was $8713.
_A
x x
b. The formula underestimates the actual answer Thus, = =1
x x
by $65.
7. −4 − (5) = −9 = 9
3. The elements common to {3, 4, 5, 6, 7} and
{3, 7, 8, 9} are 3 and 7. The distance between –4 and 5 is 9.
PP
{3, 4,5, 6, 7} ∩ {3, 7,8,9} = {3, 7}
8. 7(4 x 2 + 3x) + 2(5 x 2 + x)
4. The union is the set containing all the elements of = 7(4 x 2 + 3 x) + 2(5 x 2 + x)
either set.
{3, 4,5, 6, 7} ∪ {3, 7,8,9} = {3, 4,5, 6, 7,8,9} = 28 x 2 + 21x + 10 x 2 + 2 x
= 38 x 2 + 23 x
RO
­ π ½
5. ® −9, − 1.3, 0, 0.3, , 9, 10 ¾
9. 6 + 4[7 − ( x − 2)]
¯ 2 ¿
= 6 + 4[7 − x + 2)]
a. Natural numbers: 9 because 9 =3 = 6 + 4[9 − x]
= 6 + 36 − 4 x
b. Whole numbers: 0, 9
VE
= 42 − 4 x

c. Integers: −9, 0, 9
Concept and Vocabulary Check P.1
d. Rational numbers: −9, − 1.3, 0, 0.3, 9
C1. expression
D
π C2. b to the nth power; base; exponent
e. Irrational numbers: , 10
2
C3. formula; modeling; models
π
?
f. Real numbers: −9, − 1.3, 0, 0.3, , 9, 10 C4. intersection; A ∩ B
2
C5. union; A ∪ B



Copyright © 2022 Pearson Education, Inc 1

, Chapter P Fundamental Concepts of Algebra


C6. natural 10.
3
6 + 5 (8 − 6) = 6 + 5 ( 2)
3


C7. whole = 6 + 5 (8)

C8. integers = 6 + 40 = 46
ST
C9. rational 11. 82 − 3(8 − 2) = 64 − 3(6)
= 64 − 18 = 46
C10. irrational
12. 82 − 4 ( 8 − 3) = 64 − 4 ( 5 ) = 64 − 20 = 44
C11. rational; irrational
5( x + 2) 5(10 + 2)
U
C12. absolute value; x, x 13. =
2 x − 14 2(10) − 14
C13. b + a ; ba 5(12)
=
VI
6
C14. a + (b + c) ; ( ab)c
= 5⋅2
C15. ab + ac = 10

C16. 0; inverse; 0; identity 7( x − 3) 7(9 − 3) 7(6)
14. = = = 7 ⋅ 3 = 21
A
2 x − 16 2(9) − 16 2
C17. inverse; 1; identity
2x + 3y
_A
C18. simplified 15. ; x = −2, y = 4
x +1
C19. a 2 ( −2 ) + 3 ( 4 ) −4 + 12 8
= = = = −8
−2 + 1 −1 −1
Exercise Set P.1
2x + y
PP
16. ; x = −2 and y = 4
1. 7 + 5(10) = 7 + 50 = 57 xy − 2 x
2 ( −2 ) + 4 −4 + 4 0
= = =0
2. 8 + 6 ( 5 ) = 8 + 30 = 38 ( −2 )( 4 ) − 2 ( −2 ) −8 + 4 4

3. 6(3) − 8 = 18 − 8 = 10 5 5
RO
17. C= (50 − 32) = (18) = 10
9 9
4. 8 ( 3) − 4 = 24 − 4 = 20 50°F is equivalent to 10°C.

5. 82 + 3(8) = 64 + 24 = 88 5 5 5
18. C= ( F − 32) = (86 − 32) = (54) = 30
9 9 9
6. 62 + 5 ( 6 ) = 36 + 30 = 66 86°F is equivalent to 30°C.
VE
19. h = 4 + 60t − 16t 2 = 4 + 60(2) − 16(2) 2
7. 7 2 − 6(7) + 3 = 49 − 42 + 3 = 7 + 3 = 10
= 4 + 120 − 16(4) = 4 + 120 − 64
8. 8 − 7 ( 8 ) + 4 = 64 − 56 + 4 = 8 + 4 = 12
2 = 124 − 64 = 60
Two seconds after it is kicked, the ball’s height is
60 feet.
D
9. 4 + 5(9 − 7)3 = 4 + 5(2)3
= 4 + 5(8) = 4 + 40 = 44
?

2 Copyright © 2022 Pearson Education, Inc

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