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Exam (elaborations)

Solutions to Reinforced Concrete Design: A Practical Approach (3rd Edition) by (Brzev, 2017) | All 13 Chapters Covered

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Access the comprehensive Solution Manual for Reinforced Concrete Design: A Practical Approach, 3rd Edition by Svetlana Brzev, available as a downloadable PDF. This manual offers fully worked-out solutions, design checks, and step-by-step explanations for reinforced concrete problems including beam, column, slab, and foundation design—perfect for structural engineering students, practicing engineers, and exam preparation. reinforced concrete design solution manual, Brzev concrete manual PDF, structural engineering answers, concrete design 3rd edition solutions, beam design PDF, column design solutions, slab & foundation worked examples, reinforced concrete homework help, concrete structural design key, practical concrete answers, civil engineering PDF guide, structural design homework, #ReinforcedConcrete, #SvetlanaBrzev, #ConcreteDesign, #SolutionManual, #StructuralEngineering, #CivilEngineering, #BeamDesign, #ColumnDesign, #SlabDesign, #FoundationDesign, #ConcreteSolutions, #EngineeringPDF, #HomeworkHelp, #ExamPrep, #TextbookSolutions, #PDFDownload

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ALL 13 CHAPTERS COVERED




SOLUTIONS MANUAL

,Chapter 1 - Solutions

__________________________________________________________________________

1.1.

a) 2.4 kPa (NBC 2005 Table 4.1.5.3)

b) 2.4 kPa (NBC 2005 Table 4.1.5.3)

c) 1.9 kPa (NBC 2005 Table 4.1.5.3)

d) 7.2 kPa (stack rooms, NBC 2005 Table 4.1.5.3)

___________________________________________________________________________

1.2.

NBC 2005 Table 4.1.5.3 prescribes occupancy live load of 2.4 kPa for classrooms with or without
fixed seats.

To determine the actual occupancy live load, add together the weight for all students in the class-
room and divide by the classroom plan area.

___________________________________________________________________________

1.3.

a) Beam properties:

width b = 350mm

depth h = 700mm
3
unit weight γ w = 24kN ⁄ m

Load analysis:

- self-weight
kN kN
b × h × γ w = 0.35m × 0.7m × 24 ------3- = 5.9 -------
m m
____________________________




Copyright © 2006 @seismicisolation
Pearson Education Canada Inc.
@seismicisolation 1-1

, kN
DL ≅ 6.0 -------
m
- Live load LL = 15kN ⁄ m
kN
Total load w = DL + LL = 6.0 + 15.0 = 21.0 -------
m




2
w×l
M s = -------------- (simply supported beam, see Table A.16)
8

kN 2
21.0 ------- ( 8.0 m )
m
= --------------------------------------------- = 168kNm
8
M s = 168kNm

b) w f = 1.25DL + 1.5LL (NBC 2005 Table 4.1.3.2)
kN
= 1.25 × 6.0 + 1.5 × 15.0 = 30.0 -------
m

kN 2
2 30 ------- ( 8.0m )
wf × l m
M f = ---------------- = --------------------------------------- = 240kNm
8 8
M f = 240kNm

___________________________________________________________________________

1.4.

a) DL = 10.0kPa

LL = 5.0kPa

Load on beam B1:

Tributary width s = 3.0m

w f = ( 1.25DL + 1.5LL ) × s



Copyright © 2006 @seismicisolation
Pearson Education Canada Inc.
@seismicisolation 1-2

, = ( 1.25 × 10.0 + 1.5 × 5.0 ) × 3.0

= 60kN ⁄ m




Load on girder G1:

Tributary width s = 8m

w f = ( 1.25DL + 1.5LL ) × s
kN
= ( 1.25 × 10.0 + 1.5 × 5.0 ) × 8.0 = 160 -------
m




Copyright © 2006 @seismicisolation
Pearson Education Canada Inc.
@seismicisolation 1-3

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