Solution Manual
For Applied Statics And Strength Of
Materials,
7th Edition Bygeorgelimbrunner
, Contents
Chapter 1 1
Chapter 2 12
Chapter 3 20
Chapter 4 49
Chapter 5 71
Chapter 6 115
Chapter 7 158
Chapter 8 177
Chapter 9 202
Chapter 10 221
Chapter 11 232
Chapter 12 267
Chapter 13 285
Chapter 14 330
Chapter 15 361
Chapter 16 398
Chapter 17 428
Chapter 18 474
Chapter 19 502
Chapter 20 513
Iii
, Solution Manual
For
Applied Statics And Strength Of Materials
Seventh Edition
George F. Limbrunner, P.E., (Inactive) Craig
T. D’allaird, P.E.
Notes:
1. The Solutions Presented Herein Are, In General, Somewhat Abbreviated To
Conserve Space. Very Little Explanation Is Furnished. Sketches Are Kept To
A Minimum. Few Checks Are Shown.
2. The Solutions Follow The Procedures Developed In The Examples In The Text.
3. The Solutions Are Based On The Limited Tables Furnished In The Text
And/Or The Appendices. The Tables Furnished Are For The Purposes Of This
Text Only And Should Not Be Used For Design.
4. The Solutions For The Design Problems Are Generally Not The Only
Solution Nor Are They Necessarily The Most Economical Solutions.
5. Please Note That Problem Numbers In The Solution Manual Are Depicted With Both Dashes
(‐) And Periods (.) Between The Chapter And Problem Numbers. These Are
Interchangeable.
6. It Should Be Noted That The Previous Editions Of The Text Used Lowercase S
To Denote Stresses. This Has Changed In The 7th Edition, But Due To Time
Constraints This Solution Manual Has Not Been Completely Updated To Reflect
Such.
7. If You Find Errors In This Manual Or In The Text, Please
Forward Them To Me At .
Craig T. D’allaird
Troy,
Ny January
2021
, Prob. 1.8
(a) 𝑐 = I √102 I + I72 = 12.21 Ft
(b) 𝑏 = √202 − 162 = 12.00 M
Prob. 1.2
(a) 𝑎 = 25 Sin 48° = 18.58 Ft
(b) 𝑏 = √252 − 18.582 = 16.73 Ft
(c) ℎ = B Sin 48° = 16.73 Sin 48° = 12.43 Ft
Prob. 1.3
𝑎 = √722 − 67.32 = 25.59 Ft
A = Cos–1(67.3/72) = 20.8
B = Sin–1(67.3/72) = 69.2°
Prob. 1.4
Ab = 28 Sin 70° = 26.3 Ft
Prob. 1.5
𝑐 = √102 + 62 = 11.6 Ft
𝜃 = Tan−1(6⁄10) = 31.0°
Prob. 1.6
𝐴𝐵 = √122 + 162 = 20 Ft
𝐵𝐶 = √122 I + 322 = 34.2 Ft
𝐴 = Tan−1(12⁄16) = 36.9°
𝐶 = Tan−1(12⁄32) = 20.6°
Prob. 1.7
Θ = Sin−1(5⁄6) = 56.4°
𝑥 = √122 + 102 = 6.63 Ft
For Applied Statics And Strength Of
Materials,
7th Edition Bygeorgelimbrunner
, Contents
Chapter 1 1
Chapter 2 12
Chapter 3 20
Chapter 4 49
Chapter 5 71
Chapter 6 115
Chapter 7 158
Chapter 8 177
Chapter 9 202
Chapter 10 221
Chapter 11 232
Chapter 12 267
Chapter 13 285
Chapter 14 330
Chapter 15 361
Chapter 16 398
Chapter 17 428
Chapter 18 474
Chapter 19 502
Chapter 20 513
Iii
, Solution Manual
For
Applied Statics And Strength Of Materials
Seventh Edition
George F. Limbrunner, P.E., (Inactive) Craig
T. D’allaird, P.E.
Notes:
1. The Solutions Presented Herein Are, In General, Somewhat Abbreviated To
Conserve Space. Very Little Explanation Is Furnished. Sketches Are Kept To
A Minimum. Few Checks Are Shown.
2. The Solutions Follow The Procedures Developed In The Examples In The Text.
3. The Solutions Are Based On The Limited Tables Furnished In The Text
And/Or The Appendices. The Tables Furnished Are For The Purposes Of This
Text Only And Should Not Be Used For Design.
4. The Solutions For The Design Problems Are Generally Not The Only
Solution Nor Are They Necessarily The Most Economical Solutions.
5. Please Note That Problem Numbers In The Solution Manual Are Depicted With Both Dashes
(‐) And Periods (.) Between The Chapter And Problem Numbers. These Are
Interchangeable.
6. It Should Be Noted That The Previous Editions Of The Text Used Lowercase S
To Denote Stresses. This Has Changed In The 7th Edition, But Due To Time
Constraints This Solution Manual Has Not Been Completely Updated To Reflect
Such.
7. If You Find Errors In This Manual Or In The Text, Please
Forward Them To Me At .
Craig T. D’allaird
Troy,
Ny January
2021
, Prob. 1.8
(a) 𝑐 = I √102 I + I72 = 12.21 Ft
(b) 𝑏 = √202 − 162 = 12.00 M
Prob. 1.2
(a) 𝑎 = 25 Sin 48° = 18.58 Ft
(b) 𝑏 = √252 − 18.582 = 16.73 Ft
(c) ℎ = B Sin 48° = 16.73 Sin 48° = 12.43 Ft
Prob. 1.3
𝑎 = √722 − 67.32 = 25.59 Ft
A = Cos–1(67.3/72) = 20.8
B = Sin–1(67.3/72) = 69.2°
Prob. 1.4
Ab = 28 Sin 70° = 26.3 Ft
Prob. 1.5
𝑐 = √102 + 62 = 11.6 Ft
𝜃 = Tan−1(6⁄10) = 31.0°
Prob. 1.6
𝐴𝐵 = √122 + 162 = 20 Ft
𝐵𝐶 = √122 I + 322 = 34.2 Ft
𝐴 = Tan−1(12⁄16) = 36.9°
𝐶 = Tan−1(12⁄32) = 20.6°
Prob. 1.7
Θ = Sin−1(5⁄6) = 56.4°
𝑥 = √122 + 102 = 6.63 Ft
