Solution Manual for Shigleys Mechanical Engineering Design 11th Edition Author:Budynas / All Chapters 1 - 20 / Full Complete A+ Graded

Solution Manual for Shigleys Mechanical Engineering
Design 11th Edition Author:Budynas / All Chapters 1 - 20 /
Full Complete A+ Graded




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, Chapter 1

Problems 1-1 through 1-6 are for student research. No standard solutions are provided.

1-7 From Fig. 1-2, cost of grinding to  0.0005 in is 270%. Cost of turning to  0.003 in is
60%.
Relative cost of grinding vs. turning = 270/60 = 4.5 times Ans.

1-8 CA = CB,

10 + 0.8 P = 60 + 0.8 P − 0.005 P 2

P 2 = 50/0.005  P = 100 parts Ans.


1-9 Max. load = 1.10 P
Min. area = (0.95)2A
Min. strength = 0.85 S
To offset the absolute uncertainties, the design factor, from Eq. (1-1) should be

1.10
nd = = 1.43 Ans.
0.85(0.95)
2




1-10 (a) X1 + X2:
x1 + x2 = X1 + e1 + X 2 + e2
error = e = ( x1 + x2 ) − ( X1 + X 2 )
= e1 + e2 Ans.
(b) X1 − X2:
x1 − x2 = X1 + e1 − ( X 2 + e2 )
e = ( x1 − x2 ) − ( X1 − X 2 ) = e1 − Ans.
(c) X1 X2: e2

x1x2 = ( X1 + e1 )( X 2 + e2 )
e = x1 x2 − X1 X 2 = X1e2 + X 2e1 + e1e2
Xe +X e =X X  e2 Ans.
e1 + 
1 2 2 1 1 2  
X X
 1 2 




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, (d) X1/X2:
x1 X1 + e1 X1  1+ X1 
e1 = =
 
x X +e X 1+ e X
2 2 2 2  2 2 
−1
 e   1+ e X   e  e  e e
e
1− 2
the −
1+    1+  1− 
2 1 1 1 2 1 2
n 1+
 X2  X2  1+ X2   X1  X2  X1 X2
e2
x1 X1
Thus, e= − X1  e2 Ans.
e1 −
x X X X X

2 2 2  1 2 


1-11 (a) x1 = 7 = 2.645 751 311 1
X1 = 2.64 (3 correct digits)
x2 = 8 = 2.828 427 124 7
X2 = 2.82 (3 correct digits)
x1 + x2 = 5.474 178 435 8
e1 = x1 − X1 = 0.005 751 311 1
e2 = x2 − X2 = 0.008 427 124 7
e = e1 + e2 = 0.014 178 435 8
Sum = x1 + x2 = X1 + X2 + e
= 2.64 + 2.82 + 0.014 178 435 8 = 5.474 178 435 8 Checks
(b) X1 = 2.65, X2 = 2.83 (3 digit significant numbers)
e1 = x1 − X1 = − 0.004 248 688 9
e2 = x2 − X2 = − 0.001 572 875 3
e = e1 + e2 = − 0.005 821 564
2 Sum = x1 + x2 = X1 + X2 + e
= 2.65 +2.83 − 0.001 572 875 3 = 5.474 178 435 8 Checks


S 16 (1000) ( )
25 103
1-12  =  =  d = 0.799 in Ans.
nd d 3 2.5
Table A-17: d = 87 in Ans.

Factor n=
S
=
( )
25 103
= 3.29 Ans.
safety:of
 16 (1000)
 (7)
3

8


n



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, 1-13 Eq. (1-5): R =  Ri = 0.98(0.96)0.94 = 0.88
i=1

Overall reliability = 88 percent Ans.




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