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TOP 2025 CHEM 151 EXAM WITH Q&A 100% GUARANTEED ANSWERS A+ SCORE

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TOP 2025 CHEM 151 EXAM WITH Q&A 100% GUARANTEED ANSWERS A+ SCORE exam 3 Indicators of spontaneity: G is negative, K is greater than 1, E cell is positive all of them 6 Fe²⁺ + Cr₂O₇²⁻ + 14 H⁺ → 2 Cr³⁺ + 6 Fe³⁺ + 7 H₂O ANSWER—Fe2+ is oxidized what's the oxidation number of S in the compound Na₂S₂O₅ ANSWER—+4 Calculate E°cell for the following reaction given the standard reduction potentials below? :Zn(s) + Cu2+(aq) → Cu(s) + Zn2+(aq) Standard Reduction PotentialsZn2+ (aq) + 2e- → Zn (s) -0.763 VCu2+ (aq) + 2e- → Cu (s) +0.34 V ANSWER— +1.1 V What is the half-life for the second order decomposition of O3 when the concentration of O3 is 2.35 × 10−6M? The rate constant for this second-order reaction is 50.4 M−1hr−1 ANSWER— 8.4 x 10^3 hr A three-step mechanism for the reaction of (CH3)3CBr and H2O is proposed? Step 1 Slow (CH3)3CBr → (CH3)3C+ + Br- Step 2 Fast (CH3)3C+ + H2O → (CH3)3COH2+ Step 3 Fast ( CH3)3COH2+ + Br- → (CH3)3COH + HBr Which is the rate-determining step? ANSWER— step 1. slow step Which of the following is the overall reaction described by the mechanism in problem 6 above? ANSWER— (CH3)3CBr + H2O → (CH3)3COH + HBr he reaction of NO2(g) and CO(g) is thought to occur in two steps: Step 1 NO + NO → N2O2 Step 2 N2O2 + O2 → 2NO2 Which if the following is an intermediate? ANSWER— N2O2 Use the method of initial rates to determine the rate law for the reaction of nitrous oxide and oxygen. 2 NO(g) + O2(g) → 2 NO2(g) Rate = k[NO]m[O2]n ( view table ) ANSWER—rate = k[NO]2[O2] Which of the following changes would quadruple the rate of reaction with a rate law of rate = k[A][B]2? ANSWER— double [B] Based on the Figure below, is Reaction A or Reaction B catalyzed? What is the role of a catalyst ANSWER—(reaction b has less activation energy) reaction b is catalyzed. the catalyst speeds up a reaction by changing the reaction mechanism, and lowering the activation energy. Calculate the rate constant (k) for the following reaction given the initial rate data below. *Hint: you must first determine the rate law before you can calculate the rate constant?. ANSWER— see paper

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‭ OP 2025 CHEM‬
T
‭151 EXAM WITH‬
‭Q&A 100%‬
‭GUARANTEED‬
‭ANSWERS A+‬
‭SCORE‬

‭ xam 3‬
e
‭Indicators of spontaneity: G is negative, K‬
‭is greater than 1, E cell is positive‬
‭all of them‬
‭6 Fe²⁺ + Cr₂O₇²⁻ + 14 H⁺ → 2 Cr³⁺ + 6 Fe³⁺ +‬
‭7 H₂O‬
‭ANSWER—Fe2+ is oxidized‬

‭ hat's the oxidation number of S in the‬
w
‭compound Na₂S₂O₅‬
‭ANSWER—+4‬

‭ alculate E°cell for the following reaction‬
C
‭given the standard reduction potentials‬
‭below?‬
‭:Zn(s) + Cu2+(aq) → Cu(s) + Zn2+(aq)‬
‭Standard Reduction PotentialsZn2+ (aq) +‬
‭2e- → Zn (s) -0.763 VCu2+ (aq) + 2e- →‬
‭Cu (s) +0.34 V‬
‭ANSWER— +1.1 V‬

‭ hat is the half-life for the second order‬
W
‭decomposition of O3 when the‬
‭concentration of O3 is 2.35 × 10−6M? The‬
‭rate constant for this second-order reaction‬
‭is 50.4 M−1hr−1‬
‭ANSWER— 8.4 x 10^3 hr‬

, ‭ three-step mechanism for the reaction of‬
A
‭(CH3)3CBr and H2O is proposed?‬
‭Step 1 Slow (CH3)3CBr → (CH3)3C+ + Br-‬
‭Step 2 Fast (CH3)3C+ + H2O →‬
‭(CH3)3COH2+‬
‭Step 3 Fast‬ ‭(‭C
‬ H3)3COH2+ + Br- →‬
‭(CH3)3COH + HBr‬
‭Which is the rate-determining step?‬
‭ANSWER— step 1. slow step‬

‭ hich of the following is the overall‬
W
‭reaction described by the mechanism in‬
‭problem 6 above?‬
‭ANSWER— (CH3)3CBr + H2O →‬
‭(CH3)3COH + HBr‬
‭he reaction of NO2(g) and CO(g) is‬
‭thought to occur in two steps:‬
‭Step 1 NO + NO → N2O2‬
‭Step 2 N2O2 + O2 → 2NO2‬

‭ hich if the following is an intermediate?‬
W
‭ANSWER— N2O2‬

‭ se the method of initial rates to determine‬
U
‭the rate law for the reaction of nitrous oxide‬
‭and oxygen.‬
‭2 NO(g) + O2(g) → 2 NO2(g) Rate =‬
‭k[NO]m[O2]n‬
‭( view table )‬
‭ANSWER—rate = k[NO]2[O2]‬

‭ hich of the following changes would‬
W
‭quadruple the rate of reaction with a rate‬
‭law of rate = k[A][B]2?‬
‭ANSWER— double [B]‬

‭ ased on the Figure below, is Reaction A‬
B
‭or Reaction B catalyzed? What is the role‬
‭of a catalyst‬
‭ANSWER—(reaction b has less‬
‭activation energy)‬
‭reaction b is catalyzed. the catalyst‬
‭speeds up a reaction by changing the‬
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