with verified answers already passed
L.index(value) - correct answer ✔✔the index where the value (or first instance of it) is stored
L.count(value) - correct answer ✔✔the number of times the value appears
L.append(value) - correct answer ✔✔place an additional value at the end of the list
L.insert(index,value) - correct answer ✔✔place an additional value at specified position
L.remove(value) - correct answer ✔✔remove a value (or the first instance of it) from the list
L.pop(index) - correct answer ✔✔remove a value from a specified position
len(L) - correct answer ✔✔number of values in list
sum(L) - correct answer ✔✔total of all values in list
max(L), min(L) - correct answer ✔✔maximum or minimum value
Dictionary Format - correct answer ✔✔Ex. capitals = {'France':'Paris', 'Egypt':'Cairo'}
Add to Dictionary - correct answer ✔✔Ex. capitals['Peru'] = 'Lima'