Exam (elaborations) WGU C785

WGU C785 Final Exam Exam QUESTIONS AND
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A portion of the HLA gene and its associated amino acid sequence are
shown below. If cytosine is deleted from codon 101, what will be the
resulting amino acid sequence?

Ser Tyr Glu

Glu Met Leu

Glu Pro Cys

Glu His Ala Asp - CORRECT ANSWER Glu Met Leu

Deletion of cytosine (C) from codon 101 leads to the DNA sequence 5'-
GAG ATG CTG AT-3', which corresponds to the amino acid sequence Glu
Met Leu.

Inheriting mutations in the BRCA-1 or BRCA-2 gene can increase an
individual's likelihood of developing breast cancer or ovarian cancer.
How can PCR be used to assess an individual's susceptibility to
developing these cancers?

PCR can be used to produce the mRNA for the BRCA-1 and BRCA-2
genes, which can then be sequenced to look for mutations.

,PCR primers can be engineered to flank the mutation of interest in the
BRCA-1 and BRCA-2 genes, and the PCR product can be sequenced to
look for mutations.

The PCR process will provide an exponential increase in the amino acid
sequence of the gene products. Then the amino acid can be sequenced
to look for mutations.

PCR primers can be engineered to sequence the BRCA-1 and BRCA-2
genes and determine whether mutations are present. - CORRECT
ANSWER PCR primers can be engineered to flank the mutation of
interest in the BRCA-1 and BRCA-2 genes, and the PCR product can be
sequenced to look for mutations.

By using primers that flank the mutation of interest, PCR can produce
DNA which can be used to determine if the mutation is present.

Which template DNA sequence would result in the amino acid proline
(Pro)?

5' - TGA - 3'

5' - TGG - 3'

5' - GGT - 3'

5' - CCC - 3' - CORRECT ANSWER 5' - TGG - 3'

The correct answer is 5'-TGG-3'. The corresponding mRNA for 5'-TGG-3'
is 3'-ACC-5', which reversed is 5'-CCA-3', a codon for the amino acid Pro.

,Legumain is an enzyme that is overexpressed in neurons in response to
traumatic brain injury (TBI). How does TBI trigger an increase in the
expression of the gene that codes for legumain?

Nucleosomes are more widely spaced, exposing the legumain gene.

DNA polymerase is able to bind to the legumain gene.

Nucleosomes become tightly packed together, preventing the binding of
transcription factors to the promoter region of the legumain gene.

Methyltransferases are up regulated and add methyl groups to the DNA
bases in the legumain gene. - CORRECT ANSWER Nucleosomes are
more widely spaced, exposing the legumain gene.

Increased nucleosome spacing leads to increased transcription and
translation (i.e. gene expression) of the Legumain gene.

Which of the following mRNA sequences can be translated into a
peptide sequence containing two amino acids?

5' - GAU CGA UAG UGG - 3'

5' - GAU CGA UGG UAG - 3'

5' - UGG UAC CAG UGA - 3'

5' - GAC CAU GCG GGG - 3' - CORRECT ANSWER 5' - GAU CGA UAG
UGG - 3'

The sequence 5' - GAU CGA UAG UGG - 3' contains a stop codon in the
3rd position, therefore, this sequence would produce a peptide
sequence with two amino acids.

, What is the mRNA sequence that would result from this coding DNA
sequence: 5' - CAG TTA GAT TCA - 3'?

5' - ACU UAG AUU GAC - 3'

5' - CUG TTU GUT TCU - 3'

5' - CAG UUA GAU UCA - 3'

5' - UGA AUC UAA CUG - 3' - CORRECT ANSWER 5' - CAG UUA GAU UCA
- 3'

The coding DNA and mRNA sequences in transcription will be identical,
except for any T in the coding DNA sequence having a corresponding to
U in the mRNA sequence. The correct answer is 5'-CAG UUA GAU UCA-
3'.

What is happening to the pH of the lungs due to exhalation?

CO2 decreases from exhalation, thus the pH of the lungs increases.

CO2 increases from exhalation, thus the pH of the lungs decreases.

CO2 decreases from exhalation, thus the pH of the lungs decreases.

CO2 increases from exhalation, thus the pH of the lungs increases. -
CORRECT ANSWER CO2 decreases from exhalation, thus the pH of the
lungs increases.

The CO2 in the lung decreases as we exhale and the H+ that was on
hemoglobin is recombined with the bicarbonate ion which produces