BNU1501
2020
SEMESTER 02
ASSIGNMENT 01
SOLUTIONS
, QUESTION 01
22,49258 to 3 decimal places
Look at the 4th decimal digit, that is 5.
Since the 4th decimal is 5 you round up the 3rd decimal value from 2 to 3
Therefore 22,49258 rounded to 3 decimal places is 22,493
Option [1]
Question 02
250,192 to 1 decimal digit
Look at the 2nd decimal digit, that is 9.
Since the 4th decimal is greater than 5 you round up the 1st decimal value from 1 to 2
Therefore 250,192 rounded to 1 decimal place is 250,2.
Option [3]
Question 03
3,496 to the nearest integer
An integer is a positive whole number.
Look at the 1st decimal digit, that is 4
Since the 1st decimal is less than 5 you round down the integer to 3.
Option [1]
Question 04
Option [4]
Question 05
The number of R1 coins is 12 coin minus the number of R5 coins which is x hence 12 less x.
Option [1]
2020
SEMESTER 02
ASSIGNMENT 01
SOLUTIONS
, QUESTION 01
22,49258 to 3 decimal places
Look at the 4th decimal digit, that is 5.
Since the 4th decimal is 5 you round up the 3rd decimal value from 2 to 3
Therefore 22,49258 rounded to 3 decimal places is 22,493
Option [1]
Question 02
250,192 to 1 decimal digit
Look at the 2nd decimal digit, that is 9.
Since the 4th decimal is greater than 5 you round up the 1st decimal value from 1 to 2
Therefore 250,192 rounded to 1 decimal place is 250,2.
Option [3]
Question 03
3,496 to the nearest integer
An integer is a positive whole number.
Look at the 1st decimal digit, that is 4
Since the 1st decimal is less than 5 you round down the integer to 3.
Option [1]
Question 04
Option [4]
Question 05
The number of R1 coins is 12 coin minus the number of R5 coins which is x hence 12 less x.
Option [1]
