1. A car accelerates uniformly from rest to a speed of 20 m/s in 10 seconds. What is the total
distance covered?
A. 50 m
B. 100 m
C. 200 m
D. 400 m
Answer: B) 100 m
Rationale: Using the formula s=ut+12at2s = ut + \frac{1}{2}at^2s=ut+21at2, where u=0u =
0u=0, v=20v = 20v=20, t=10t = 10t=10, and a=v−ut=20−010=2a = \frac{v - u}{t} = \frac{20 -
0}{10} = 2a=tv−u=1020−0=2 m/s², we get s=0+12×2×102=100s = 0 + \frac{1}{2} \times 2
\times 10^2 = 100s=0+21×2×102=100 m.
2. A body is moving with a uniform velocity of 5 m/s for 4 seconds. What is the distance
traveled by the body?
A. 5 m
B. 10 m
C. 15 m
D. 20 m
Answer: D) 20 m
Rationale: Distance = velocity × time. So, 5×4=205 \times 4 = 205×4=20 m.
3. A 3 kg object is attached to a spring with a spring constant of 200 N/m. What is the extension
in the spring when the object is at rest?
A. 0.1 m
B. 0.15 m
C. 0.2 m
D. 0.25 m
,Answer: A) 0.1 m
Rationale: Using Hooke’s law, F=kxF = kxF=kx, where F=mg=3×9.8=29.4F = mg = 3 \times 9.8
= 29.4F=mg=3×9.8=29.4 N, and k=200k = 200k=200 N/m. So, x=Fk=29.4200=0.147≈0.1x =
\frac{F}{k} = \frac{29.4}{200} = 0.147 \approx 0.1x=kF=20029.4=0.147≈0.1 m.
4. A 2 kg object is moving with a speed of 6 m/s. What is its momentum?
A. 10 kg·m/s
B. 12 kg·m/s
C. 14 kg·m/s
D. 16 kg·m/s
Answer: B) 12 kg·m/s
Rationale: Momentum p=mv=2×6=12p = mv = 2 \times 6 = 12p=mv=2×6=12 kg·m/s.
5. A particle is subjected to a constant force of 10 N. If its mass is 5 kg, what is its acceleration?
A. 0.5 m/s²
B. 1 m/s²
C. 2 m/s²
D. 5 m/s²
Answer: C) 2 m/s²
Rationale: Using F=maF = maF=ma, we have a=Fm=105=2a = \frac{F}{m} = \frac{10}{5} =
2a=mF=510=2 m/s².
6. A car accelerates at 2 m/s² for 5 seconds from rest. What distance does it cover in that time?
A. 25 m
B. 30 m
C. 50 m
D. 75 m
Answer: B) 30 m
, Rationale: Using the formula s=ut+12at2s = ut + \frac{1}{2}at^2s=ut+21at2, where u=0u =
0u=0, a=2a = 2a=2 m/s², and t=5t = 5t=5 s. So, s=0+12×2×52=30s = 0 + \frac{1}{2} \times 2
\times 5^2 = 30s=0+21×2×52=30 m.
7. A particle is moving with a uniform velocity of 2 m/s for 10 seconds. What distance does the
particle cover?
A. 5 m
B. 15 m
C. 20 m
D. 25 m
Answer: C) 20 m
Rationale: Distance = velocity × time,
2×10=202 \times 10 = 202×10=20 m.
8. A particle moves in a circle with radius 5 m. If the particle has a speed of 10 m/s, what is its
centripetal acceleration?
A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 20 m/s²
Answer: C) 10 m/s²
Rationale: Centripetal acceleration is given by ac=v2ra_c = \frac{v^2}{r}ac=rv2,
ac=1025=20a_c = \frac{10^2}{5} = 20ac=5102=20 m/s².
9. A car with a mass of 1000 kg is moving at 15 m/s. What is its kinetic energy?
A. 112,500 J
B. 150,000 J
C. 225,000 J
distance covered?
A. 50 m
B. 100 m
C. 200 m
D. 400 m
Answer: B) 100 m
Rationale: Using the formula s=ut+12at2s = ut + \frac{1}{2}at^2s=ut+21at2, where u=0u =
0u=0, v=20v = 20v=20, t=10t = 10t=10, and a=v−ut=20−010=2a = \frac{v - u}{t} = \frac{20 -
0}{10} = 2a=tv−u=1020−0=2 m/s², we get s=0+12×2×102=100s = 0 + \frac{1}{2} \times 2
\times 10^2 = 100s=0+21×2×102=100 m.
2. A body is moving with a uniform velocity of 5 m/s for 4 seconds. What is the distance
traveled by the body?
A. 5 m
B. 10 m
C. 15 m
D. 20 m
Answer: D) 20 m
Rationale: Distance = velocity × time. So, 5×4=205 \times 4 = 205×4=20 m.
3. A 3 kg object is attached to a spring with a spring constant of 200 N/m. What is the extension
in the spring when the object is at rest?
A. 0.1 m
B. 0.15 m
C. 0.2 m
D. 0.25 m
,Answer: A) 0.1 m
Rationale: Using Hooke’s law, F=kxF = kxF=kx, where F=mg=3×9.8=29.4F = mg = 3 \times 9.8
= 29.4F=mg=3×9.8=29.4 N, and k=200k = 200k=200 N/m. So, x=Fk=29.4200=0.147≈0.1x =
\frac{F}{k} = \frac{29.4}{200} = 0.147 \approx 0.1x=kF=20029.4=0.147≈0.1 m.
4. A 2 kg object is moving with a speed of 6 m/s. What is its momentum?
A. 10 kg·m/s
B. 12 kg·m/s
C. 14 kg·m/s
D. 16 kg·m/s
Answer: B) 12 kg·m/s
Rationale: Momentum p=mv=2×6=12p = mv = 2 \times 6 = 12p=mv=2×6=12 kg·m/s.
5. A particle is subjected to a constant force of 10 N. If its mass is 5 kg, what is its acceleration?
A. 0.5 m/s²
B. 1 m/s²
C. 2 m/s²
D. 5 m/s²
Answer: C) 2 m/s²
Rationale: Using F=maF = maF=ma, we have a=Fm=105=2a = \frac{F}{m} = \frac{10}{5} =
2a=mF=510=2 m/s².
6. A car accelerates at 2 m/s² for 5 seconds from rest. What distance does it cover in that time?
A. 25 m
B. 30 m
C. 50 m
D. 75 m
Answer: B) 30 m
, Rationale: Using the formula s=ut+12at2s = ut + \frac{1}{2}at^2s=ut+21at2, where u=0u =
0u=0, a=2a = 2a=2 m/s², and t=5t = 5t=5 s. So, s=0+12×2×52=30s = 0 + \frac{1}{2} \times 2
\times 5^2 = 30s=0+21×2×52=30 m.
7. A particle is moving with a uniform velocity of 2 m/s for 10 seconds. What distance does the
particle cover?
A. 5 m
B. 15 m
C. 20 m
D. 25 m
Answer: C) 20 m
Rationale: Distance = velocity × time,
2×10=202 \times 10 = 202×10=20 m.
8. A particle moves in a circle with radius 5 m. If the particle has a speed of 10 m/s, what is its
centripetal acceleration?
A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 20 m/s²
Answer: C) 10 m/s²
Rationale: Centripetal acceleration is given by ac=v2ra_c = \frac{v^2}{r}ac=rv2,
ac=1025=20a_c = \frac{10^2}{5} = 20ac=5102=20 m/s².
9. A car with a mass of 1000 kg is moving at 15 m/s. What is its kinetic energy?
A. 112,500 J
B. 150,000 J
C. 225,000 J
