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Business Math 11th Edition Cleaves Solutions Manual.pdf

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Business Math 11th Edition Cleaves Solutions M

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March 25, 2025
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,ACCESS Test Bank for Business Mathematics In Canada 11th Canadian Edition J
m m m m m m m m m m m

rome



1
Review and Applications m m m




of Basic Mathematics
m m




Exercisem1.1
a. 10m+m10mx m0m=m10m+m0m=m10
b. 2mx m2m+m4m–m8m=m4m+m4m–m8m=m0
c. (10m+m10)mx m0m=m20mx m0m=m0
d. 2mx m(2m+m4)m–m8m=m2mx m6m–m8m=m12m–m8m=m4
e. 0m+m3mx m3m–m32m+m10m=m0m+m9m–m9m+m10m=m10
f. 12m–m2mx m5m+m22mx m0m=m12m–m10m+m4mx m0m=m12m–m10m+m0m=m2
g. 0m+m3mx m3m–m(32m+m10)m=m0m+m9m–m19m=m-10
h. (12m–m2)mx m(5m+m22)mx m0m=m10mx m9mx m0m=m0
2 2 m−m4 m 4 m− m4 m 0 m
i. =m =m =m0
(4−m 2)2 22 4

(2 m−m4)2 mm (−2 )2 mm 4 m
j. =m =m =4
5−m2 2 5 m−m4 1

1. 20m−m4mm2m−m8m=m20m−m8m−m8m=m 4
2. 18mm3m+m6mm2m=m6m+m12m=m18
3. (20 − 4)  2 − 8 = 16  2 − 8 = 32 − 8 = 24
m m m m m m m m m m m m m m m m m m



4. 18mm(3m+m6)mm2m=m18m m9m m2m=m2mm2m= m4

5. 20m−m(4mm2m−m8)m=m20m−m(8m−m8)m=m20

6. (18  3 m m m +m6)mm2m=m(6m+m6)mm2m=m24

7. 54m−m36mm4m+m2 2m =m54m−m9m+m4m= m49

8. (5 + 3)2 − 32  9 + 3 = 82
m m
m
m m m m m m m m −m9mm9m+m3m= m64m−m1+m3m=m 66

9. (54 m −m36)mm(4m+m2)
2m
=m18mm62m =m18mm36m=m0.5

10. 5m+m 32m−m3 ( )2  (9 + 3) = 5 + (9 − 3)2  12 = 5 + 36  12 = 5 + 3 = 8
m
m m m m m m m m m
m
m m m m m m m m m m m m m



82m−m4 64m−m16m 48m
11. 2 =m =m6
= 8
(4 − 2)
m m
23
3


12.
(8 − 4)
m m
=m m
42
=
16m
=m−m4
2m
4m− m 4m−m8 −m4
23


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,13. 3(6m+m4)2m −m5(17m−m20)2m =m3102m−m5(−m3)2m =m3100m−m59 m=m300m−m45m=m255



Chapterm1:mReviewmandmApplicationsmofmBasicmMathematics 1




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, ACCESS Test Bank for Business Mathematics In Canada 11th Canadian Edition J
m m m m m m m m m m m

rome


14. (4  3 − 2)2  (4 − 3  22 )= (12 − 2)2  (4 − 3  4) = 102  (4 − 12) = 100  (− 8) = − 12.5
m m m m
m
m m m m m m m m m
m
m m m m m m m m m m m m m m m m m m m



15. (20 + 8  5) − 7  (− 3) 9 = (20 + 40 + 21)  9 = 81 9 = 9
m m m m m m m m m m m m m m m m m m m m m m m




16. 519 +m 52m−m1
 ( )22m
m

= 5 19 +m(2 −m1 )2m  2m
5(19m+ 81)2m 5mm10 2
m =m5
m 0,000

6  5 6 = = 0
17. $100(1+m0.06mm365
45m m
)=m$100(1+m0.00739726)m=m$100.74
$200 $200m $200m
18. =m =m =m$194.1
1+m0.09mm12 1+m0.0
m 7m1.03
4m 3
$500 $500m $500m
19. 2 =m =m$453.51
(1m+m0.05) = 2 1.1025
1.05

( )
20. $1000m( 1+ m 0.02) =m $1000m 1.023 m = m $1000m(1.061208 m) m=m $1061.21
3m

m(1+m0.04)2m −m m1.042m −m1 m0.0816m
1 
21. $100 0.04 m =m$100 0.04 m =m$100 0.04 m =m$204.00
 
     
 1 m 1 m
1−m m
1−m
 m
m1−m0.942596
 ( 1+ m0.03)
2m
 1.0609 m



22. $300 m =m$300 m =m$300 m =m$574.04
 0.03   0.03   0.03 
   
   

ConceptmQuestionsm (Sectionm1.2)
1. Yoummustmretainmatmleastmonemmoremfiguremthanmyoumrequireminmthemanswer.mTomachievemf
our-
mfiguremaccuracy minmthemanswer,myoummustmretainmamminimummofmfivemfiguresminmthemvalue

smusedminmthemcalculations.mB)
2. Wemwantmsix-
figuremaccuracy minmthemanswer.mTherefore,mvaluesmusedminmthemcalculationsmmustmbem
accuratemtomatmleastmsevenmfigures.mB)
3. Wemwantmseven-
figuremaccuracy minmthemanswer.mTherefore,mvaluesmusedminmthemcalculationsmmustmretainm
atmleastmeightmfigures.mC)
4. Tombemaccuratemtomthemnearestm0.01%,manminterestmratemgreatermthanm10%mmustmhavemf
our-
mfiguremaccuracy.mTherefore,mfivemfiguresmmustmbemretainedminmnumbersmusedminmthemcal

culations.mC)

Exercisem1.2
a. 1
10
=m0.10m=m10%
b. 2m =m0.40m=m40%

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