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CHEM 219 Module 7 Problem Set Principles of Organic Chemistry | Portage Learning | 2025/2026 Guide

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CHEM 219 Module 7 Problem Set Principles of Organic Chemistry | Portage Learning | 2025/2026 Guide CHEM 219 Module 7 Problem Set Principles of Organic Chemistry | Portage Learning | 2025/2026 Guide CHEM 219 Module 7 Problem Set Principles of Organic Chemistry | Portage Learning | 2025/2026 Guide

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12/14/23, 8:43 PM Module 7 Problem Set: Principles of Organic Chemistry with Lab-2021-Gallaher




CHEM 219 Module 7 Problem Set Principles of
Organic Chemistry | Portage Learning | 2025/2026
Guide

Score for this quiz: 10 out of 10
Submitted Dec 3 at 3:23am
This attempt took 26 minutes.


Question 1 pts


Define the term heterocycle as it applies to organic molecules.

Your Answer:

Heterocycles (heterocyclic compounds) are cyclic organic molecules in
which one or more carbon atoms are replaced by heteroatoms – elements
other than carbon or hydrogen.




Answer:

Heterocycles (heterocyclic compounds) are cyclic organic
molecules in which one or more carbon atoms are replaced by
heteroatoms – elements other than carbon or hydrogen.




Question 2 pts

, 12/14/23, 8:43 PM Module 7 Problem Set: Principles of Organic Chemistry with Lab-2021-Gallaher




What are the two main sub-groups of heterocyclic compounds?


Your Answer:

aromatic and non-aromatic




Answer:

Aliphatic and Aromatic




Question 3 pts

Explain why pyridine is soluble in water.


Your Answer:

Pyridine can accept hydrogen bonding interactions due to the lone pair of
electrons in nitrogen. And the electronegative N creates a relatively strong
dipole moment, making it a polar compound.




Answer:

There are several factors that explain the ability of pyridine to
dissolve in water. First is the ability of pyridine to accept
hydrogen bonding interactions from water molecules due to
the lone pair of electrons on the nitrogen atom. In addition,
the electronegative nitrogen creates a relatively strong dipole
moment in the pyridine molecule, thus making pyridine a
polar compound overall.




Question 4 pts

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