Bio 340 Exam 3 - Questions And Answers With
Verified Solutions Graded A+ Latest Update 2025.
TTGACA - ANSWER the -35 consensus sequence in prokaryotes
the TATAAT sequence that is often found at the -10 region of bacterial promoters - ANSWER
Pribnow Box
The prokaryotic ribosome-binding site on mRNA, found about 10 nucleotides 5' to the start codon
AGGAGGU - ANSWER Shine-Dalgarno sequence
AUG (methionine) - ANSWER start codon
TATAAA - ANSWER TATA box sequence
codes for addition of the poly-A-tail AATAAA - ANSWER polyadenylation signal
~2 m - ANSWER The haploid human genome is 3 Gbp long (3x10^9 bp). How long would the
genomic DNA in a single diploid cell in your body be if it were stretched out end to end?
100 billion Km - ANSWER The haploid human genome is 3 Gbp long (3x10^9 bp). There are
approximately 50 trillion cells in the human body. How long would all of the human genomic DNA in
your body be if it were stretch out end to end?
6- ANSWER If there are 6 C's in the DNA sequence, how many G's are there?
DNA-dependent RNA polymerase - ANSWER What kind of enzyme is primase?
Ligase - ANSWER Which of the following components is not involved during the formation of
the replication fork?
b. Cancer cells
c. Pluripotent stem cells
d. Adult B lymphocytes
e. b, c and d are correct - ANSWER In what cells would you expect to see telomerase activity?
Guanine - ANSWER Which base will thymine (enol) pair with in DNA?
A transition mutation - ANSWER A tautomeric shift may result in:
, 600,000 - ANSWER How many mutations would you expect to see in the human genome if
mismatches could not be repaired?
10^-6 mutations/base pair - ANSWER Proofreading removes approximately 99% of
mismatches before DNA replication moves on. After proofreading what is the mutation rate for DNA
replication in humans?
6,000 - ANSWER Proofreading removes approximately 99% of mismatches before DNA
replication moves on. How many mutations would you expect to see in the human genome if mismatches
can be repaired by proofreading?
DNA polymerase proofreading - ANSWER The initial mechanism for repairing nucleotide
errors in DNA is ________.
Frameshift mutations - ANSWER What types of mutations can intercalating agents lead to?
Direct repair - ANSWER Which of the following is the type of DNA repair in which thymine
dimers are directly broken down by the enzyme photolyase?
E. All except frameshift mutations
a. Missense mutations
b. Nonsense mutations
c. Frameshift mutations
d. Regulatory mutations - ANSWER The graph shows the results of an Ames test to identify the
the effect of several concentrations of Aflatoxin B using a couple of his- Salmonella strains (TA 100 and
TA 1538). While TA 100 is a strain sensitive to reversion mutations by base substitutions, TA 1538 is
sensitive to frameshift mutations. Based on the results, what kind of mutations can Aflatoxin B1 lead to?
It is used to identify mutants with restored biosynthetic activity. - ANSWER Which of the
following regarding the Ames test is true?
TATAAT - ANSWER Which sequence would you predict to be at a promoter site?
Leucine - ANSWER Which amino acid would you expect to be part of an alpha-helix from the
GPCR signaling protein?
41-101 - ANSWER For the eukaryotic DNA sequence shown, what region of the DNA will be
transcribed into mRNA?
(First find the TATA box and the polyadenylation sequences, then think about the location of the
sequences with respect to the final length of the mRNA.)
Verified Solutions Graded A+ Latest Update 2025.
TTGACA - ANSWER the -35 consensus sequence in prokaryotes
the TATAAT sequence that is often found at the -10 region of bacterial promoters - ANSWER
Pribnow Box
The prokaryotic ribosome-binding site on mRNA, found about 10 nucleotides 5' to the start codon
AGGAGGU - ANSWER Shine-Dalgarno sequence
AUG (methionine) - ANSWER start codon
TATAAA - ANSWER TATA box sequence
codes for addition of the poly-A-tail AATAAA - ANSWER polyadenylation signal
~2 m - ANSWER The haploid human genome is 3 Gbp long (3x10^9 bp). How long would the
genomic DNA in a single diploid cell in your body be if it were stretched out end to end?
100 billion Km - ANSWER The haploid human genome is 3 Gbp long (3x10^9 bp). There are
approximately 50 trillion cells in the human body. How long would all of the human genomic DNA in
your body be if it were stretch out end to end?
6- ANSWER If there are 6 C's in the DNA sequence, how many G's are there?
DNA-dependent RNA polymerase - ANSWER What kind of enzyme is primase?
Ligase - ANSWER Which of the following components is not involved during the formation of
the replication fork?
b. Cancer cells
c. Pluripotent stem cells
d. Adult B lymphocytes
e. b, c and d are correct - ANSWER In what cells would you expect to see telomerase activity?
Guanine - ANSWER Which base will thymine (enol) pair with in DNA?
A transition mutation - ANSWER A tautomeric shift may result in:
, 600,000 - ANSWER How many mutations would you expect to see in the human genome if
mismatches could not be repaired?
10^-6 mutations/base pair - ANSWER Proofreading removes approximately 99% of
mismatches before DNA replication moves on. After proofreading what is the mutation rate for DNA
replication in humans?
6,000 - ANSWER Proofreading removes approximately 99% of mismatches before DNA
replication moves on. How many mutations would you expect to see in the human genome if mismatches
can be repaired by proofreading?
DNA polymerase proofreading - ANSWER The initial mechanism for repairing nucleotide
errors in DNA is ________.
Frameshift mutations - ANSWER What types of mutations can intercalating agents lead to?
Direct repair - ANSWER Which of the following is the type of DNA repair in which thymine
dimers are directly broken down by the enzyme photolyase?
E. All except frameshift mutations
a. Missense mutations
b. Nonsense mutations
c. Frameshift mutations
d. Regulatory mutations - ANSWER The graph shows the results of an Ames test to identify the
the effect of several concentrations of Aflatoxin B using a couple of his- Salmonella strains (TA 100 and
TA 1538). While TA 100 is a strain sensitive to reversion mutations by base substitutions, TA 1538 is
sensitive to frameshift mutations. Based on the results, what kind of mutations can Aflatoxin B1 lead to?
It is used to identify mutants with restored biosynthetic activity. - ANSWER Which of the
following regarding the Ames test is true?
TATAAT - ANSWER Which sequence would you predict to be at a promoter site?
Leucine - ANSWER Which amino acid would you expect to be part of an alpha-helix from the
GPCR signaling protein?
41-101 - ANSWER For the eukaryotic DNA sequence shown, what region of the DNA will be
transcribed into mRNA?
(First find the TATA box and the polyadenylation sequences, then think about the location of the
sequences with respect to the final length of the mRNA.)
