Solution Manual for Engineering Circuit Analysis 9th Edition Hayt / All Chapters 1 - 18 / Full Complete 2023

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Engineering9 0 Circuit9 0 Analysis Chapter9 0 Two9 0 Exercise90Solut
9th90Editio ions
n
1. Convert90the90following90to90engineering90notation:

(a) 0.04590W9 0 90459010390 W90=904590mW

(b) 200090pJ90902000901012909029010990J90=90290nJ

(c) 0.190ns90900.11099090100901 =9010090ps
01290s

(d) 39,21290as90=903.9212×104×10-1890=9039.212×10-1539.212
90s90= 90f
s
(e)90390
Ω
(f) 18,00090 901890103m=90 1890 km
m

(g) 2,500,000,000,00090bits9 0 902.59010129 0 bits90 =902.590terabits
3
9010159 0 atoms90 901029 0 cm90219 0
(h)    90310 atoms/ (it’s90unclear90what90a90“zeta90atom”90is)
m
 cm3  9 0 9 0 190m 




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