TSI Math Test Preperation
10 people can paint a building in 5 days. If each person paints as quickly as the
others then how much of the building could 7 people paint in 5 days? - ANS - 10
people can paint a building in 5 days. Each person paints 1/10 of the building in 5
days. In 5 days 7 people would paint 7 × 1/10 of the building In 5 days 7 people
would paint 7/10 of the building.
\A ball was kicked into the air from a balcony 20 feet above the ground, and the
ball's height above the ground, in feet, t seconds after the ball was kicked was
h(t) = 20 − 16t2 + 32t. What was the maximum height, in feet, of the ball above the
ground after it was kicked? - ANS - h(t) = 20-16t^2 + 32t
h(t) = -16t^2 +32+20
x= -b /2a = -(32)/2(-16) = -32/-32 = 1
Plug one in the original equation.
h(1) = -16(1)^2 +32+20
= -16+32+20
The answer is 36 ft
\An isosceles triangle has two equal sides. If two of the sides are 5 inches and 2
inches how long is the perimeter? - ANS - The other side must be 5 inches
otherwise the two shorter sides could not meet. The perimeter is the distance
around the outside of the triangle and is 5 + 5 + 2 = 12.
\Bill's new porch is rectangular, with an area of 50 square feet. If the length of the
porch is two times the width, what is the perimeter of the porch? - ANS - The
formula for the area of a rectangle:
A = Width * Length
From the question we know that L = 2W and that A = 50. So we can plug these
values into our equation and solve for W:
50 = W * L
50 = W * 2W
50 = 2W²
W² = 25
W=5
We know that L = 2W, so L = 10
10 people can paint a building in 5 days. If each person paints as quickly as the
others then how much of the building could 7 people paint in 5 days? - ANS - 10
people can paint a building in 5 days. Each person paints 1/10 of the building in 5
days. In 5 days 7 people would paint 7 × 1/10 of the building In 5 days 7 people
would paint 7/10 of the building.
\A ball was kicked into the air from a balcony 20 feet above the ground, and the
ball's height above the ground, in feet, t seconds after the ball was kicked was
h(t) = 20 − 16t2 + 32t. What was the maximum height, in feet, of the ball above the
ground after it was kicked? - ANS - h(t) = 20-16t^2 + 32t
h(t) = -16t^2 +32+20
x= -b /2a = -(32)/2(-16) = -32/-32 = 1
Plug one in the original equation.
h(1) = -16(1)^2 +32+20
= -16+32+20
The answer is 36 ft
\An isosceles triangle has two equal sides. If two of the sides are 5 inches and 2
inches how long is the perimeter? - ANS - The other side must be 5 inches
otherwise the two shorter sides could not meet. The perimeter is the distance
around the outside of the triangle and is 5 + 5 + 2 = 12.
\Bill's new porch is rectangular, with an area of 50 square feet. If the length of the
porch is two times the width, what is the perimeter of the porch? - ANS - The
formula for the area of a rectangle:
A = Width * Length
From the question we know that L = 2W and that A = 50. So we can plug these
values into our equation and solve for W:
50 = W * L
50 = W * 2W
50 = 2W²
W² = 25
W=5
We know that L = 2W, so L = 10
