AP Physics 2 - Electrostatics FRQ Test Questions and Answers

AP Physics 2 - Electrostatics FRQ Test
Questions and Answers

Electron Source


b. Calculate the magnitude between the electric field between the plates. ✅✅E = V/d KE =


mv²/2 - mv²/2


1.602x10⁻¹⁷ = 1.6x10⁻¹⁹ x V


V = 100.097


E = 100.097/.01




E = 10,009.73 N/C




Electron Source


c. Calculate the magnitude of the charge on each plate. ✅✅C = ke(A/d) =


1(8.85x10⁻¹²)(.25/.01) = 2.2125x10⁻¹⁰


C = Q/V


2.2125x10⁻¹⁰ = Q/100.097

, Q = 2.215x10⁻⁸ C




Two parallel conducting plates


b. Determine the potential difference between the plates. ✅✅V = 100 V




Two parallel conducting plates


c. Determine the capacitance of this arrangement of plates. ✅✅C = 1.328x10⁻¹⁰ F




Two parallel conducting plates


An electron is initially located at a point midway between the plates.




d. Determine the magnitude of the electrostatic force on the electron at this location and state


its direction. ✅✅F = 8x10⁻¹⁶ N toward positive plate (right)




Two parallel conducting plates