100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached 4.2 TrustPilot
logo-home
Class notes

Vector Analysis Topics review, guaranteed and verified 100% Pass

Rating
-
Sold
-
Pages
18
Uploaded on
28-12-2024
Written in
2024/2025

Vector Analysis, guaranteed and verified 100% PassVector Analysis, guaranteed and verified 100% PassVector Analysis, guaranteed and verified 100% PassVector Analysis, guaranteed and verified 100% PassVector Analysis, guaranteed and verified 100% PassVector Analysis, guaranteed and verified 100% PassVector Analysis, guaranteed and verified 100% Pass

Show more Read less
Institution
Math
Course
Math










Whoops! We can’t load your doc right now. Try again or contact support.

Written for

Institution
Math
Course
Math

Document information

Uploaded on
December 28, 2024
Number of pages
18
Written in
2024/2025
Type
Class notes
Professor(s)
Auroux, denis
Contains
All classes

Content preview

A Quick Review of a few Topics from 3rd Semester Calculus

1. Vectors in 𝑅 3

A vector in 𝑅 3 is a line segment from the origin (0,0,0) to a point in 𝑅 3,
(𝑎, 𝑏, 𝑐). We denote this vector by < 𝑎, 𝑏, 𝑐 >.



(𝑎, 𝑏, 𝑐)




(0,0,0)




We can also write this vector as:

< 𝑎, 𝑏, 𝑐 >= 𝑎𝑖⃗ + 𝑏𝑗⃗ + 𝑐𝑘⃗⃗;

where 𝑖⃗ =< 1,0,0 > , 𝑗⃗ =< 0,1,0 > , 𝑘⃗⃗ =< 0,0,1 >.

Ex. < 2,5, −1 >= 2𝑖⃗ + 5𝑗⃗ − 𝑘⃗⃗ .



We can add or subtract vectors by adding or subtracting their components.

Ex. < 2, −3, 4 > +< 5, 0, −2 >=< 7, −3, 2 >

< 3, 2, −4 > −< 5, −1, 2 > =< −2, 3, −6 >

, 2



< 2, −3,4 >




< 5,0, −2 >



< 7, −3,2 >

< 5,0, −2 >




We can also multiply a vector by a real number (called a scalar), by multiplying
each of the components.


Ex. (−6) < 3, −2, −3 > =< −18, 12, 18 >.


There are 2 ways to multiply vectors in 𝑅 3, through a "Dot" product (whose
answer is a number, not a vector), and through a "Cross" product (whose answer
is a vector not a number).

Let 𝑣⃗1 =< 𝑎1 , 𝑏1 , 𝑐1 > and 𝑣⃗2 =< 𝑎2 , 𝑏2 , 𝑐2 >.


Dot Product:

𝑣⃗1 ∙ 𝑣⃗2 = 𝑎1 𝑎2 + 𝑏1 𝑏2 + 𝑐1 𝑐2

Note: 𝑣⃗1 ∙ 𝑣⃗2 is a real number, NOT a vector.

Ex. < 2, −3,4 >∙< 5,0, −2 >= (2)(5) + (−3)(0) + (4)(−2) = 10 + 0 − 8 = 2.

, 3


Notice that: 𝑣⃗1 ∙ 𝑣⃗1 = 𝑎1 2 + 𝑏1 2 + 𝑐1 2 = ‖𝑣⃗1 ‖2

or ‖𝑣⃗1 ‖ = √𝑣⃗1 ∙ 𝑣⃗1 = √𝑎1 2 + 𝑏1 2 + 𝑐1 2



Properties of the Dot product:

1. 𝑣⃗1 ∙ 𝑣⃗2 = 𝑣⃗2 ∙ 𝑣⃗1

2. 𝑣⃗1 ∙ (𝑣⃗2 + 𝑣⃗3 ) = 𝑣⃗1 ∙ 𝑣⃗2 + 𝑣⃗1 ∙ 𝑣⃗3



If 𝑣⃗ = 𝑎𝑖⃗ + 𝑏𝑗⃗ + 𝑐𝑘⃗⃗ , 𝑣⃗ ≠ ⃗⃗
0, then a unit vector (a vector of length 1) in the
direction of 𝑣⃗ is given by:

⃗⃗
𝑣 𝑎 𝑏 𝑐
𝑢
⃗⃗ = ‖𝑣⃗⃗‖ = 𝑖⃗ + 𝑗⃗ + 𝑘⃗⃗
√𝑎2 +𝑏 2 +𝑐 2 √𝑎 2 +𝑏 2 +𝑐 2 √𝑎 2 +𝑏 2 +𝑐 2



Ex. Find a unit vector in the direction of 𝑣⃗ =< 2, −2,1 > = 2𝑖⃗ − 2𝑗⃗ + 𝑘⃗⃗



Here 𝑎 = 2, 𝑏 = −2, 𝑐 = 1, so 𝑎2 + 𝑏 2 + 𝑐 2 = 4 + 4 + 1 = 9.
𝑎 𝑏 𝑐
𝑢
⃗⃗ = 𝑖⃗ + 𝑗⃗ + ⃗⃗ = 2 𝑖⃗ − 2 𝑗⃗ + 1 𝑘⃗⃗
𝑘
√𝑎 2 +𝑏 2 +𝑐 2 √𝑎 2+𝑏 2 +𝑐 2 √𝑎 2 +𝑏 2 +𝑐 2 3 3 3




Theorem: Assume 𝑣⃗, 𝑤 ⃗⃗. Then 𝑣⃗ ∙ 𝑤
⃗⃗⃗ ≠ 0 ⃗⃗⃗ = 0 if and only if 𝑣⃗ and 𝑤
⃗⃗⃗ are
perpendicular.
$11.39
Get access to the full document:

100% satisfaction guarantee
Immediately available after payment
Both online and in PDF
No strings attached

Get to know the seller
Seller avatar
sudoexpert119

Also available in package deal

Thumbnail
Package deal
Vector Analysis Full Course notes
-
15 2024
$ 170.95 More info

Get to know the seller

Seller avatar
sudoexpert119 Harvard University
View profile
Follow You need to be logged in order to follow users or courses
Sold
0
Member since
1 year
Number of followers
0
Documents
411
Last sold
-
A+ Smart Scholars Studio

Ace your exams with trusted, expertly crafted resources built for top-tier results.

0.0

0 reviews

5
0
4
0
3
0
2
0
1
0

Recently viewed by you

Why students choose Stuvia

Created by fellow students, verified by reviews

Quality you can trust: written by students who passed their tests and reviewed by others who've used these notes.

Didn't get what you expected? Choose another document

No worries! You can instantly pick a different document that better fits what you're looking for.

Pay as you like, start learning right away

No subscription, no commitments. Pay the way you're used to via credit card and download your PDF document instantly.

Student with book image

“Bought, downloaded, and aced it. It really can be that simple.”

Alisha Student

Frequently asked questions