·
newton's second law ·
straight line analysis
·
when a net force ac ts on a object wl mass , the object's velocity changes
·
the object accelerates &
T
·
impulse -
momentum theorem
·
an impulse applied to a system changes the system's momentum Pf
the magnitude of the change i n momentum i s equal to the impulse applied
D
J =
AP
Po
F.
At = DMV
the slope of the line represents a 1 : 1 ratio of Po:pf
question 3 since momentum is conserved
·
↳ the expected slope is 1
·
free-body diagram during collision when carts are in contact and Po =
Pf
m/s when
the intercept represents the value of Pf in kg
.
- N a
N
Po is zero
-"A
B ↑
FC ↳ the expected intercept is O Since Po = Pf & when Po =
O
- ·
mg
then Pf = O
mg
Fc : Force A exerts
#c : Force Bexerts ·
uncertainty
on A on B
p =
my
·
question 4 DP = Am .
V + m .
DV
compare net forces
·
the net force on Carts Ad B are equal bic the forces they exerted
·
on each other during the collision are equal in magnitude a opposite
in direction
↳ according to newton's third law , every action has an equal but opposite reaction
question 5
·
compare net forces at different time collision
·
in
Fa would still be equal to Fd but opposite direc tions the contact forces
·
. of
the two carts start out equal a decrease at the same rate over that period of time
question G
·
total momentum of the collision
·
the total momentum i s zero because the sum of net forces of the system equals zero
Fsystem =
FA-FB = O
↑
equal magnitude
opposite direction
question 7
·
·
what is the total change in momentum
the total momentum is zero since momentum i s conserved bic the sum of all forces is zero
·
conservation of momentum
on the system momentum is conserved
if there are no net external forces acting ,
Fad Fr are internal to our system
types of collisions
·
·
elastic collision
·
carts do not stick , & KE conserved
momentum
·
inelastic collision
·
carts stick ,
momentum conserved & KE not conserved