Solving Linear Equations: Variables on Both
Sides/ Questions & Correct Answers/ 2024-
2025.
What is the solution to the linear equation?
2/5 + p = 4/5 + 3/5p - Answer: p = 1
Which number can each term of the equation be multiplied by to
eliminate the decimals before solving?
-m + 0.02 + 2.1m = -1.45 _ 4.81m - Answer: 100
Page 1 of 6
, Which number can each term of the equation be multiplied by to
eliminate the decimals before solving?
5.6j - 0.12 = 4 + 1.1j - Answer: 100
What is the solution to the linear equation?
4b + 6 = 2 - b + 4 - Answer: b = 0
The levels of mercury in two different bodies of water are rising. In one
body of water the initial measure of mercury is 0.05 parts per billion
(ppb) and is rising at a rate of 0.1 ppb each year. In the second body of
water the initial measure is 0.12 ppb and the rate of increase is 0.06
ppb each year.
Which equation can be used to find y, the year in which both bodies of
water have the same amount of mercury? - Answer: 0.05 + 0.1y = 0.12
+ 0.06y
Page 2 of 6
Sides/ Questions & Correct Answers/ 2024-
2025.
What is the solution to the linear equation?
2/5 + p = 4/5 + 3/5p - Answer: p = 1
Which number can each term of the equation be multiplied by to
eliminate the decimals before solving?
-m + 0.02 + 2.1m = -1.45 _ 4.81m - Answer: 100
Page 1 of 6
, Which number can each term of the equation be multiplied by to
eliminate the decimals before solving?
5.6j - 0.12 = 4 + 1.1j - Answer: 100
What is the solution to the linear equation?
4b + 6 = 2 - b + 4 - Answer: b = 0
The levels of mercury in two different bodies of water are rising. In one
body of water the initial measure of mercury is 0.05 parts per billion
(ppb) and is rising at a rate of 0.1 ppb each year. In the second body of
water the initial measure is 0.12 ppb and the rate of increase is 0.06
ppb each year.
Which equation can be used to find y, the year in which both bodies of
water have the same amount of mercury? - Answer: 0.05 + 0.1y = 0.12
+ 0.06y
Page 2 of 6
