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UGA Math Placement Test with Verified Answers |Latest 2024/2025

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UGA Math Placement Test with Verified Answers. Interval notation Bracket= definite, parentheses = indefinite the maximum of a negative quadratic is located at the vertex Quadratic Formula x equals -b plus or minus the square root of b squared minus four ac over 2a the rule that generates a function is y=f(x) rational expression a fraction where the numerator and denominator are polynomials x=5 (lin equation) 1 solution 4=5 (lin equation) 0 solutions 5=5 (lin equation) infinite solutions distance formula d squared= delta x squared plus delta y squared

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Institution
UGA Math Placement
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UGA Math Placement









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Institution
UGA Math Placement
Course
UGA Math Placement

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Uploaded on
September 13, 2024
Number of pages
7
Written in
2024/2025
Type
Exam (elaborations)
Contains
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UGA Math Placement Test with Verified
_’- _’- _’- _’- _’- _’-




Answers. _’-




Interval notation
_’- _’-_’- _’- Bracket= definite, parentheses = indefinite
_’- _’- _’- _’-




the maximum of a negative quadratic is located at
_’- _’- _’- _’- _’- _’- _’- _’- _’-_’- _’- the vertex
_’-




Quadratic Formula _’- x equals -b plus or minus the square root of b
_’-_’- _’- _’- _’- _’- _’- _’- _’- _’- _’- _’- _’- _’-


squared minus four ac over 2a
_’- _’- _’- _’- _’-




the rule that generates a function is
_’- _’- _’- _’- _’- _’- _’-_’- _’- y=f(x)


rational expression
_’- _’-_’- _’- a fraction where the numerator and denominator are
_’- _’- _’- _’- _’- _’- _’- _’-


polynomials


x=5 (lin equation)
_’- _’- _’-_’- _’- 1 solution
_’-




4=5 (lin equation)
_’- _’- _’-_’- _’- 0 solutions
_’-




5=5 (lin equation)
_’- _’- _’-_’- _’- infinite solutions _’-




distance formula
_’- _’-_’- _’- d squared= delta x squared plus delta y squared
_’- _’- _’- _’- _’- _’- _’- _’-

, Slope Intercept Formula
_’- _’- _’-_’- _’- y=mx+b


Point Slope Formula
_’- _’- _’-_’- _’- y-y1=m(x-x1)


Two Point Formula
_’- _’- _’-_’- _’- y-y1=(y2-y1)/(x2-x1) x (x-x1) _’- _’-




Standard Form of a Line _’- _’- _’- _’- _’-_’- _’- ax plus by equals c
_’- _’- _’- _’-




if dividing an inequality by a negative number
_’- _’- _’- _’- _’- _’- _’- _’-_’- _’- flip the sign
_’- _’-




x to the -n
_’- _’- _’- _’-_’- _’- 1 divided by x to the n
_’- _’- _’- _’- _’- _’-




x to the 1/n
_’- _’- _’- _’-_’- _’- n root x
_’- _’-




x to the p/n
_’- _’- _’- _’-_’- _’- (n square root) to p
_’- _’- _’- _’-




x to the a times x to the b
_’- _’- _’- _’- _’- _’- _’- _’- _’-_’- _’- x to the a plus b
_’- _’- _’- _’- _’-




(xy) to the a
_’- _’- _’- _’-_’- _’- x to the a times x to the b
_’- _’- _’- _’- _’- _’- _’- _’-




x to the a / x to the b
_’- _’- _’- _’- _’- _’- _’- _’- _’-_’- _’- x to the a minus b
_’- _’- _’- _’- _’-




(x/y) to the a
_’- _’- _’- _’-_’- _’- x to the a divided by x to the b
_’- _’- _’- _’- _’- _’- _’- _’- _’-

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