LON-CAPA HOMEWORK 10
A ball of mass 3 kg is uniformly increased from rest and travels 48 m in 4 s. What is its final
kinetic power after 4 s? - ANSFirst: Calculate the acceleration of the ball the use of ∆x = ½at².
Second: Use the acceleration to find the force performing at the ball, and then take into account
that the exchange in Kinetic Energy equals the net work accomplished on it (W = F∆x). (Don't
worry about preliminary because it starts at rest)
ANS: 864 J
A 1-kg ball within the air has an initial pace vi = [ 20 ] i + [ -30 ] j m/s. It falls for a total time of 1
s. Assume that superb x-values are to the proper and fine y-values are upward.
What is the initial momentum pi of the ball? - ANSRemember that the preliminary momentum pi
= mvo = [ mvxo ] i + [ mvyo ] j.
ANS: [20]i + [-30] j kg/m*s
A 1-kg ball within the air has an preliminary pace vi = [ 20 ] i + [ -30 ] j m/s. It falls for a total time
of one s. Assume that fine x-values are to the right and wonderful y-values are upward.
What is the impulse or alternate in momentum ∆p of the ball? - ANSRemember that the impulse
I = ∆p = F∆t = [-mg∆t] j. (no i component). The force is gravity within the poor y-path.
ANS: [0]i + [-10] j kg/m*s
A 1-kg ball inside the air has an preliminary velocity vi = [ 20 ] i + [ -30 ] j m/s. It falls for a
complete time of one s. Assume that wonderful x-values are to the proper and advantageous
y-values are upward.
What is the final momentum pf of the ball? - ANSRemember that the very last momentum pf = pi
+ ∆p = [ pxi ] i + [ pyi + ∆py ] j. Note that ∆px = 0 in this hassle since no pressure acts in the
x-direction.
ANS: [20]i + [-40] j kg/m*s
A 1-kg ball within the air has an initial pace vi = [ 20 ] i + [ -30 ] j m/s. It falls for a complete time
of 1 s. Assume that fine x-values are to the right and fine y-values are upward.
What is the preliminary kinetic energy Ki of the ball? - ANSRemember that the preliminary
kinetic power Ki = (pxi² + pyi²)/2m
, ANS: (four hundred + 900)/2*1 ==> 650 J
A 1-kg ball in the air has an initial velocity vi = [ 20 ] i + [ -30 ] j m/s. It falls for a total time of 1 s.
Assume that advantageous x-values are to the proper and high quality y-values are upward.
What is the final kinetic power Kf of the ball? - ANSRemember that the final kinetic electricity Kf
= (pxf2 + pyf2)/2m.
ANS: (four hundred + 1600)/2*1 ==> 1000 J
A 1-kg ball in the air has an initial velocity vi = [ 20 ] i + [ -30 ] j m/s. It falls for a complete time of
one s. Assume that high-quality x-values are to the proper and advantageous y-values are
upward.
What is the alternate in kinetic electricity ∆K of the ball? - ANSRemember that the alternate in
kinetic power ∆K = Kf − Ki.
ANS: one thousand J - 650 J = 350 J
A 1-kg ball within the air has an preliminary velocity vi = [ 20 ] i + [ -30 ] j m/s. It falls for a total
time of one s. Assume that superb x-values are to the proper and positive y-values are upward.
What is the ball's exchange in height ∆y after it falls 1 s? - ANSRemember that the internet work
on the ball Wnet = ∆K = W1E * ∆y. Do not forget about that the ball is falling, so its alternate in
top is poor.
ANS: 350J = (-10) * ∆y ==> ∆y = -35 m
Puck 1 (0.Five kg) travels with velocity 40 m/s to the proper when it collides with % 2 (2 kg)
that's initially at rest. After the collision, % 1 actions with a velocity of -8 m/s. Assume that no
outside forces are gift and therefore the momentum for the system of pucks is conserved.
What is the final velocity, V₂f, of p.C. 2 after the collision? - ANSSince the entire momentum of
the gadget is conserved, the preliminary general momentum (= m1v1i) equals the final total
momentum (=m1v1f + m2v2f). You are given the loads of both pucks and of the three velocities,
which is enough records to resolve for v2f.
ANS: (0.5*40m/s) = (zero.5*-8m/s)+(2*V₂f) ==> V₂f = 12 m/s
A spinning disk is rotating at a fee of 2 rad/s within the counterclockwise route as shown within
the determine. Assume that the initial angular velocity is positive.
What is the route of the angular velocity vector? - ANSRemember to wrap your right hand in the
route of rotation and your thumb will give the direction of the angular speed.
A ball of mass 3 kg is uniformly increased from rest and travels 48 m in 4 s. What is its final
kinetic power after 4 s? - ANSFirst: Calculate the acceleration of the ball the use of ∆x = ½at².
Second: Use the acceleration to find the force performing at the ball, and then take into account
that the exchange in Kinetic Energy equals the net work accomplished on it (W = F∆x). (Don't
worry about preliminary because it starts at rest)
ANS: 864 J
A 1-kg ball within the air has an initial pace vi = [ 20 ] i + [ -30 ] j m/s. It falls for a total time of 1
s. Assume that superb x-values are to the proper and fine y-values are upward.
What is the initial momentum pi of the ball? - ANSRemember that the preliminary momentum pi
= mvo = [ mvxo ] i + [ mvyo ] j.
ANS: [20]i + [-30] j kg/m*s
A 1-kg ball within the air has an preliminary pace vi = [ 20 ] i + [ -30 ] j m/s. It falls for a total time
of one s. Assume that fine x-values are to the right and wonderful y-values are upward.
What is the impulse or alternate in momentum ∆p of the ball? - ANSRemember that the impulse
I = ∆p = F∆t = [-mg∆t] j. (no i component). The force is gravity within the poor y-path.
ANS: [0]i + [-10] j kg/m*s
A 1-kg ball inside the air has an preliminary velocity vi = [ 20 ] i + [ -30 ] j m/s. It falls for a
complete time of one s. Assume that wonderful x-values are to the proper and advantageous
y-values are upward.
What is the final momentum pf of the ball? - ANSRemember that the very last momentum pf = pi
+ ∆p = [ pxi ] i + [ pyi + ∆py ] j. Note that ∆px = 0 in this hassle since no pressure acts in the
x-direction.
ANS: [20]i + [-40] j kg/m*s
A 1-kg ball within the air has an initial pace vi = [ 20 ] i + [ -30 ] j m/s. It falls for a complete time
of 1 s. Assume that fine x-values are to the right and fine y-values are upward.
What is the preliminary kinetic energy Ki of the ball? - ANSRemember that the preliminary
kinetic power Ki = (pxi² + pyi²)/2m
, ANS: (four hundred + 900)/2*1 ==> 650 J
A 1-kg ball in the air has an initial velocity vi = [ 20 ] i + [ -30 ] j m/s. It falls for a total time of 1 s.
Assume that advantageous x-values are to the proper and high quality y-values are upward.
What is the final kinetic power Kf of the ball? - ANSRemember that the final kinetic electricity Kf
= (pxf2 + pyf2)/2m.
ANS: (four hundred + 1600)/2*1 ==> 1000 J
A 1-kg ball in the air has an initial velocity vi = [ 20 ] i + [ -30 ] j m/s. It falls for a complete time of
one s. Assume that high-quality x-values are to the proper and advantageous y-values are
upward.
What is the alternate in kinetic electricity ∆K of the ball? - ANSRemember that the alternate in
kinetic power ∆K = Kf − Ki.
ANS: one thousand J - 650 J = 350 J
A 1-kg ball within the air has an preliminary velocity vi = [ 20 ] i + [ -30 ] j m/s. It falls for a total
time of one s. Assume that superb x-values are to the proper and positive y-values are upward.
What is the ball's exchange in height ∆y after it falls 1 s? - ANSRemember that the internet work
on the ball Wnet = ∆K = W1E * ∆y. Do not forget about that the ball is falling, so its alternate in
top is poor.
ANS: 350J = (-10) * ∆y ==> ∆y = -35 m
Puck 1 (0.Five kg) travels with velocity 40 m/s to the proper when it collides with % 2 (2 kg)
that's initially at rest. After the collision, % 1 actions with a velocity of -8 m/s. Assume that no
outside forces are gift and therefore the momentum for the system of pucks is conserved.
What is the final velocity, V₂f, of p.C. 2 after the collision? - ANSSince the entire momentum of
the gadget is conserved, the preliminary general momentum (= m1v1i) equals the final total
momentum (=m1v1f + m2v2f). You are given the loads of both pucks and of the three velocities,
which is enough records to resolve for v2f.
ANS: (0.5*40m/s) = (zero.5*-8m/s)+(2*V₂f) ==> V₂f = 12 m/s
A spinning disk is rotating at a fee of 2 rad/s within the counterclockwise route as shown within
the determine. Assume that the initial angular velocity is positive.
What is the route of the angular velocity vector? - ANSRemember to wrap your right hand in the
route of rotation and your thumb will give the direction of the angular speed.
