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What is the wavelength of peak emittance (mu m) for an object of temperature 6000 k? Round to the
nearest 100th. - 𝜆𝑚𝑎𝑥 =(2897𝜇𝑚𝐾/T) =(2897𝜇𝑚𝐾/6000K) =0.48±0.1 𝜇𝑚
Solve for X. X=(41 x 10^8)^1/4 - X=253.04
The wavelength of peak emittance for the sun is included in which region of the electromagnetic
spectrum? - Visible
According to Labert's Cosine law, the intensity of radiation hitting a surface is dependent on the cosine
of the angle of incidence. According to the Stefan-Boltzman law, hotter objects emit more power than
colder objects - True
Use the graph at the following link to answer the question:
https://docs.google.com/spreadsheets/d/1Bnf-
V8smRH1oPGrcioCNHeraO9Ozlsm_xfM_e54o_Ms/edit?usp=sharing. What radiation law does this graph
depict? - The graph shows how, according to Beer's Law, the fraction of radiation that gets transmitted
decreases exponentially with each layer it passes through, like leaf layers in a canopy.
What is the mass of Agron in the atmosphere? - 6.8 x 10∧16 kg
When the atmosphere is unstable, a rising parcel will ____, when the atmosphere is stable a rising
parcel is____. - Continue to rise; fall back to its original height
If the atmosphere has a lapse rate of 10°Ckm∧-1 it is considered unstable - True
Calculate l∨surface for l∨beam = 1000 Wm∧-2 and θ= 60° using Lambert's cosine law. - 500 Wm^-2
How would you answer from 9 change if you were 1% further away? (Hint: use the inverse square law
and substitute 1.01 for d to get your new l∨beam then recalculate l∨surface). - It would be smaller, 490
Wm^-2