MIP1502
ASSIGNMENT 4
ANSWERS 2024
Due DATE: 16 AUGUST 2024
,MIP1502
Assignment 4: Compulsory
Contributes 25% to the final pass mark
Unique number: 397869
Due date: 16 August 2024
Question 1
1.1 A tiling design is made by orchestrating dark and red squares, as displayed
below:\
1.1.1 Complete the table beneath for tile numbers 5 and 6.
complete the table beneath for tile numbers 5 and 6 (6 focuses):
To find the missing qualities for tile numbers 5 and 6, how about we first really look
at the examples in the given information:
- The quantity of red squares \( R \) follows a math succession with a typical contrast
of 2:
- 4, 6, 8, 10 ...
- It gives off an impression of being \( R = 2n + 2 \).
, - The quantity of dark squares \( B \):
- 5, 10, 17, 26...
- The distinction advances as follows:
- Contrast: 5, 7, 9 (which increments by 2 each time)
- Thusly, it seems to follow a quadratic grouping. We can communicate this as a
polynomial condition.
To work out the complete squares \( S \) for tile numbers 5 and 6:
- The complete number of squares is by all accounts the square of the tile length \( l
\).
- The relationship \( S = l^2 \); where \( l \) is 3 (for tile number 1), so almost certainly,
each tile length is \( n + 2 \).
Accepting tile number \( n \):
- For \( n = 5 \), \( l \) would approach 5, and for tile \( n = 6 \), \( l \) would rise to 6.
Thus, squares will be:
- \( 5^2 = 25 \)
- \( 6^2 = 36 \)
Utilizing these perceptions, we can finish the table:
ASSIGNMENT 4
ANSWERS 2024
Due DATE: 16 AUGUST 2024
,MIP1502
Assignment 4: Compulsory
Contributes 25% to the final pass mark
Unique number: 397869
Due date: 16 August 2024
Question 1
1.1 A tiling design is made by orchestrating dark and red squares, as displayed
below:\
1.1.1 Complete the table beneath for tile numbers 5 and 6.
complete the table beneath for tile numbers 5 and 6 (6 focuses):
To find the missing qualities for tile numbers 5 and 6, how about we first really look
at the examples in the given information:
- The quantity of red squares \( R \) follows a math succession with a typical contrast
of 2:
- 4, 6, 8, 10 ...
- It gives off an impression of being \( R = 2n + 2 \).
, - The quantity of dark squares \( B \):
- 5, 10, 17, 26...
- The distinction advances as follows:
- Contrast: 5, 7, 9 (which increments by 2 each time)
- Thusly, it seems to follow a quadratic grouping. We can communicate this as a
polynomial condition.
To work out the complete squares \( S \) for tile numbers 5 and 6:
- The complete number of squares is by all accounts the square of the tile length \( l
\).
- The relationship \( S = l^2 \); where \( l \) is 3 (for tile number 1), so almost certainly,
each tile length is \( n + 2 \).
Accepting tile number \( n \):
- For \( n = 5 \), \( l \) would approach 5, and for tile \( n = 6 \), \( l \) would rise to 6.
Thus, squares will be:
- \( 5^2 = 25 \)
- \( 6^2 = 36 \)
Utilizing these perceptions, we can finish the table:
