ANSWERS WITH SOLUTIONS 2024
How can we tell from a distance-time graph if an object is stationary? - ANSWER The
distance-time graph for any object is stationary is a horizontal line.
How can we tell from a distance-time graph if an object is moving at constant speed? -
ANSWER The distance-time graph for any object that is moving at a constant speed is
a straight line that slopes upwards.
What does the gradient of a distance-time graph tell us? - ANSWER The gradient of a
distance-time graph for an object represents the objects speed.
How do we calculate the speed of an object? - ANSWER Speed in m/s = distance
travelled in m/time taken in s.
What is the difference between speed and velocity? - ANSWER Velocity is speed in a
given direction.
What is acceleration and what is its unit? - ANSWER Acceleration is the change of
velocity per second. The unit of acceleration is in m/s2.
How can we calculate the acceleration of an object? - ANSWER Acceleration = change
of velocity/time taken.
What is deceleration? - ANSWER Deceleration is the change of velocity per second
when an object slows down.
What can we say if a velocity-time graph is a horizontal line? - ANSWER If a velocity-
time graph is a horizontal line, the acceleration is zero.
How can we tell from a velocity-time graph if an object is accelerating or decelerating? -
ANSWER The gradient of the line on a velocity-time graph represents acceleration.
What does the area under a velocity-time graph represent? - ANSWER The area under
the line on a velocity-time graph represents distance travelled.
How can we calculate speed from a distance-time graph? - ANSWER The speed of an
object is given by the gradient of the line on its distance-time graph.
How can we calculate acceleration from a velocity-time graph? - ANSWER The
acceleration of an object s given by the gradient of the line on its velocity-time graph.
How can we calculate distance from a velocity-time graph? - ANSWER The distance
travelled by an object is given by the area under the line of its velocity-time graph.