Chapter 8 Multiple Choice
Questions AP Chem Review
Exam Question and Complete
solution
Denning [Date] [Course title]
, A student titrates 20.0 mL of 1.0 M NaOH with 2.0 M formic acid, HCO2H (K sub a = 1.8 x 10^-4). Formic
acid is a monoprotic acid.
How much formic acid is necessary to reach the equivaelnce point?
a- 10.0 mL
b- 20.0 mL
c- 30.0 mL
d- 40.0 mL - Correct Answer a- 10.0 mL
A student titrates 20.0 mL of 1.0 M NaOH with 2.0 M formic acid, HCO2H (K sub a = 1.8 x 10^-4). Formic
acid is a monoprotic acid.
At the equivalence point, is the solution acidic, basic, or neutral? Why?
a- acidic; the strong acid dissociates more than the weak base
b- basic; the only ion present at equilibrium is the conjugate base
c- basic; the higher concentration of the base is the determining factor
d- neutral; equal moles of both acid and base are present - Correct Answer b- basic; the only ion present
at equilibrium is the conjugate base
A student titrates 20.0 mL of 1.0 M NaOH with 2.0 M formic acid, HCO2H (K sub a = 1.8 x 10^-4). Formic
acid is a monoprotic acid.
If the formic acid were replaced with a strong acid such as HCl at the same concentration (2.0 M), how
would tht change the vollume needed to reach the equivalence point?
a- the change would reduce the amount as the acid now fully dissociates
b- the change would reduce the amount because the base will be more strongly attracted to the acid
c- the change would increse the amount because the reaction will now go to completion instead of
equilibrium
d- changing the strength of the acid will not change the volume needed to reach equivalence - Correct
Answer d- changing the strength of the acid will not change the volume needed to reach equivalence
Questions AP Chem Review
Exam Question and Complete
solution
Denning [Date] [Course title]
, A student titrates 20.0 mL of 1.0 M NaOH with 2.0 M formic acid, HCO2H (K sub a = 1.8 x 10^-4). Formic
acid is a monoprotic acid.
How much formic acid is necessary to reach the equivaelnce point?
a- 10.0 mL
b- 20.0 mL
c- 30.0 mL
d- 40.0 mL - Correct Answer a- 10.0 mL
A student titrates 20.0 mL of 1.0 M NaOH with 2.0 M formic acid, HCO2H (K sub a = 1.8 x 10^-4). Formic
acid is a monoprotic acid.
At the equivalence point, is the solution acidic, basic, or neutral? Why?
a- acidic; the strong acid dissociates more than the weak base
b- basic; the only ion present at equilibrium is the conjugate base
c- basic; the higher concentration of the base is the determining factor
d- neutral; equal moles of both acid and base are present - Correct Answer b- basic; the only ion present
at equilibrium is the conjugate base
A student titrates 20.0 mL of 1.0 M NaOH with 2.0 M formic acid, HCO2H (K sub a = 1.8 x 10^-4). Formic
acid is a monoprotic acid.
If the formic acid were replaced with a strong acid such as HCl at the same concentration (2.0 M), how
would tht change the vollume needed to reach the equivalence point?
a- the change would reduce the amount as the acid now fully dissociates
b- the change would reduce the amount because the base will be more strongly attracted to the acid
c- the change would increse the amount because the reaction will now go to completion instead of
equilibrium
d- changing the strength of the acid will not change the volume needed to reach equivalence - Correct
Answer d- changing the strength of the acid will not change the volume needed to reach equivalence
