CHEM 121 Final Exam Questions and Answers – Portage Learning

CHEM 121 Final Exam Questions and Answers – Portage Learning. Do the three conversions shown below, showing all work: 1. 328 K = ? oC 2. 76oC = ? oF 3. 135oF = ? K Your Answer: 1 - 328 - 273 = 55 C 2 - (76x 1.8) + 32 = 168.8 F 3 - (135 - 32) / 1.8 = 57.2 C + 273 = 330.2 K 1. 328K - 273 = 55 oC K → oC(make smaller) -273 2. 76oC x 1.8 + 32 = 168.8 oF C → o oF (make larger) x 1.8 + 32 3. 135oF - 32 ÷ 1.8 = 57.2 + 273 = 330.2 K oF → oC →K Question 2 Not yet graded / 10 pts You may find the following resources helpful: Scientific Calculator (Links to an external site.) Periodic Table Equation Table Classify each of the following 3 as an element, compound, solution or heterogeneous mixture and explain your answer. 1. Wine 2. Tomato soup 3. Tin Your Answer: 1 - solution 2 - heterogeneous mixture 3 - element 1. Solution; Wine - is not on periodic table (not element) - no element names (not compound) appears to be one substance = Solution 2. Solution; Tomato soup - is not on periodic table (not element) - no element name(not compound) appears to be one substance = Solution 3. Element; Tin - is on periodic table = Element Question 3 Not yet graded / 10 pts You may find the following resources helpful: Scientific Calculator (Links to an external site.) Periodic Table Equation Table Show the calculation of the number of grams in the given amount of the following 2 substances. Report your answer to 1 place after the decimal. 1. 1.20 moles of Al2(CO3)3 2. 1.04 moles of C8H6NO4Cl Your Answer: grams = moles x molecular weight 1 - mw = 233.99 x 1.2 = 280.788 ~ 280.8 2 - mw = 215.588 x 1.04 = 224.21152 ~ 224.2 1. Grams = Moles x molecular weight = 1.20 x 233.99 = 280.8 grams 2. Grams = Moles x molecular weight = 1.04 x 215.59 = 224.2 grams Question 4 Not yet graded / 10 pts