100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached 4.2 TrustPilot
logo-home
Summary

Summary Topic 9 - Derivatives of Carboxylic Acids

Rating
-
Sold
1
Pages
7
Uploaded on
14-06-2019
Written in
2018/2019

These are the complete notes for the CCEA A2 1 specification and have been created through multiple sources. However, they are not endorsed by CCEA.

Institution
Course








Whoops! We can’t load your doc right now. Try again or contact support.

Written for

Study Level
Examinator
Subject
Unit

Document information

Uploaded on
June 14, 2019
Number of pages
7
Written in
2018/2019
Type
Summary

Subjects

Content preview

Chemistry
Topic 9: Derivatives of Carboxylic Acids

Physical Properties
Boiling Points
The small esters have boiling points which are similar to those of aldehydes and ketones with a
similar RMM.

Like aldehydes and ketones, they are polar molecules and so have dipole-dipole interactions –
because of polar C=O group as well as Van der Waals dispersion forces. However, they don’t form
hydrogen bonds (as there is no hydrogen bonded to an oxygen) and so their boiling points aren’t
anything like as high as an acid with the same number of carbon atoms.
Molecule Type Boiling point
(oC) An alkyl chain in ester increases – boiling point
CH3COOCH2CH3 Ester 77.1 increases as increasing number of electrons
CH3CH2CH2COOH Carboxylic 164 causes Van der Waals forces of attraction
Acid between molecules.


Solubility in water
The small esters are fairly soluble in water, but solubility falls with chain length.
Ester Structural Formula Solubility (g per 100g of water)
Ethyl methanoate HCOOCH2CH3 10.5
Ethyl ethanoate CH3COOCH2CH3 8.7
Ethyl Propanoate CH3CH2COOCH2CH3 1.7

In a similar way to aldehydes and ketones, esters can’t hydrogen bond with themselves, they can
hydrogen bond with water molecules.

One of the slightly positive hydrogen atoms in a water molecule can be sufficiently attracted to one
of the lone pairs on one of the oxygen atoms in an ester for a hydrogen bond to be formed.

There will also, of course, be Van der Waals dispersion forces and dipole-dipole attractions between
the ester and the water molecules.

Forming these attractions releases energy. This helps to supply the energy needed to separate water
molecule from water molecule and ester molecule from ester molecule before they can mix
together.

As chain lengths increase, the hydrocarbon parts of the ester molecules start to get in the way.
Longer chains force themselves between water molecules, breaking the relatively strong hydrogen
bonds between water molecules without replacing them by anything as strong (Van der Waals). This
makes the process energetically less profitable and so solubility decreases.




Ester
$4.14
Get access to the full document:

100% satisfaction guarantee
Immediately available after payment
Both online and in PDF
No strings attached

Get to know the seller
Seller avatar
JArchy123

Get to know the seller

Seller avatar
JArchy123 CCEA
Follow You need to be logged in order to follow users or courses
Sold
12
Member since
6 year
Number of followers
2
Documents
10
Last sold
1 year ago

0.0

0 reviews

5
0
4
0
3
0
2
0
1
0

Recently viewed by you

Why students choose Stuvia

Created by fellow students, verified by reviews

Quality you can trust: written by students who passed their tests and reviewed by others who've used these notes.

Didn't get what you expected? Choose another document

No worries! You can instantly pick a different document that better fits what you're looking for.

Pay as you like, start learning right away

No subscription, no commitments. Pay the way you're used to via credit card and download your PDF document instantly.

Student with book image

“Bought, downloaded, and aced it. It really can be that simple.”

Alisha Student

Frequently asked questions