Exam (elaborations)
Portage Learning CHEM 104 Module 4 Exam
Rating
Sold
1
Pages
11
Grade
A+
Uploaded on
05-03-2024
Written in
2023/2024
Portage Learning CHEM 104 Module 4 Exam.Question 1 For the cell described by the following cell diagram. Cr (s) | Cr+3 (aq, 1 M) || Al+3 (aq, 1 M) | Al (s) Al+3 + 3e- → Al E0 = - 1.66 v Cr+3 + 3e- → Cr E0 = - 0.73 v (1) The anode half reaction is (2) The cathode half reaction is (3) The overall cell reaction is (4) Show the calculation for the total cell potential (5) State and explain whether the cell is voltaic or electrolytic Your Answer: 1) Cr (s) → Cr+3 (aq) + 3e- 2) Al+3 (aq) + 3e- → Al (s) 3) Cr (s) + Al+3 (aq) → Cr+3 (aq) + Al (s) 0 0 0 cathode anode E0 cell = -1.66 - (-0.73) E0 cell = -0.93 v 5) Since the total cell potential is negative, cell will not occur spontaneously and would have to be electrolytic.
Show more
Read less
Institution
Portage Learning CHEM 104 Module 4
Course
Portage Learning CHEM 104 Module 4
Whoops! We can’t load your doc right now. Try again or contact support.
Written for
- Institution
- Portage Learning CHEM 104 Module 4
- Course
- Portage Learning CHEM 104 Module 4
Document information
- Uploaded on
- March 5, 2024
- Number of pages
- 11
- Written in
- 2023/2024
- Type
- Exam (elaborations)
- Contains
- Questions & answers
Subjects
-
portage learning chem 104 module 4 exam
$13.49
Get access to the full document:
100% satisfaction guarantee
Immediately available after payment
Both online and in PDF
No strings attached
