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Portage Learning CHEM 104 Module 4 Exam
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Portage Learning CHEM 104 Module 4 ExamQuestion 1 For the cell described by the following cell diagram. Cr (s) | Cr+3 (aq, 1 M) || Al+3 (aq, 1 M) | Al (s) Al+3 + 3e- → Al E0 = - 1.66 v Cr+3 + 3e- → Cr E0 = - 0.73 v (1) The anode half reaction is (2) The cathode half reaction is (3) The overall cell reaction is (4) Show the calculation for the total cell potential (5) State and explain whether the cell is voltaic or electrolytic Your Answer: 1) Cr (s) → Cr+3 (aq) + 3e- 2) Al+3 (aq) + 3e- → Al (s) 3) Cr (s) + Al+3 (aq) → Cr+3 (aq) + Al (s) 0 0 0 cathode anode E0 cell = -1.66 - (-0.73) E0 cell = -0.93 v 5) Since the total cell potential is negative, cell will not occur spontaneously and would have to be electrolytic.
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Portage Learning CHEM 104 Module 4
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Portage Learning CHEM 104 Module 4
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portage learning chem 104 module 4 exam
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