PORTAGE LEARNING CHEMISTRY 103 FINAL EXAM STUDY GUIDE MODULES

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CHEM 103 Final Exam (Version-1,
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CHEM 103 General Chemistry Final
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PORTAGE LEARNING
CHEMISTRY 103 FINAL
EXAM STUDY GUIDE
MODULES

1-6

MODULE 1

– EXAM

Question 1 –
Section 1.1 10
/ 10 pts
Complete the two problems below:

1. Convert 1005.3 to exponential form and explain your answer.

2. Convert 4.87 x 10-6 to ordinary

form and explain your answer. Your

Answer:



1.) Convert 1005.3 to exponential form and explain your answer:

,All number values must be between 1-10. Because this value is greater than 1, the exponent remains
positive.

In order for this to happen, we have to move the decimal three places to the LEFT thus, the exponential
form of 1005.3 is: 1.0053 X 103



2.) Convert 4.87 x 10-6 to ordinary form and explain your answer.

All number values must be between 1-10. Because this value has a


negative exponent, the final answer will be less than 1. In order for this


to happen, we have to move the decimal six places to the LEFT thus:


0.00000487

Quest
ion 2
10 /
10 pts
Complete the two problems below:

Using the following information, do the conversions shown below, showing all work:
1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts




1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints
kilo (= 1000) milli (= 1/1000) centi (= 1/100) deci (= 1/10)




1. 3.6 pounds = ? oz

2. 2680 ml =

? liters Your

Answer:



1.) 3.6 pounds = 57.6 oz

1lb = 16oz

,3.6(16) / 1 =57.6 oz



2.) 2680 ml = 2.68 liters

New/Old


Liters/Mi


lliliters

, 1L = 1,000mL

2,680/1,000

=2.68

Quest
ion 3
10 /
10 pts
Do the conversions shown below, showing all work:

1. 78oC = ? oK

2. 248oF = ? oC

3. 427oK = ? oF
Your Answer:


Kelvin is the


larger


Fahrenheit is


the middle


Celcius is the


smaller




1.) 78oC = 351 oK

Add:

273+78 = 351K




2.) 248oF = 120 oC