Unit 18 Assignment C
C: Inves1gate chemical equilibrium in order to understand the extent to which reac1ons go
to comple1on
1
, What is an equilibrium?
When a chemical reac1on reaches an equilibrium the reactants and their concentra1on
remain the same, this would mean that products would not change and would also remain
the same. Both the forward and backward reac1on have not ceased to con1nue but are
going on at the exact rate of one another. In summary, the rate of a forward reac1on is
equivalent to the rate of a reverse reac1on.
rate vs 1me graphs are a great way to depict no change in reactants or products in an
equilibrium. This could be said the same for concentra1on vs 1me graphs where different
concentra1ons of a reactant can s1ll lead to an equilibrium.
hHp://www.dynamicscience.com.au/tester/solu1ons1/chemistry/equilibrium/Lesson%203-
%20equilibriumgraphs.pdf
How do certain factors affect the posi9on of an equilibrium and the effect of Kc?
Increase/decrease in temperature
The formula/expression for equilibrium constant is as follows:
[C ]c [D]d
Kc =
[A]a [B]b
Temperature is the only factor that affects the value of equilibrium constant (Kc). If the
temperature is increased, this would affect the posi1on of the equilibrium and would move
towards the direc1on of the endothermic reac1on, this would cause the equilibrium to
move to the right. Increasing the temperature of a reac1on causes the equilibrium constant
(Kc) to go up in value. If I was to work out the equilibrium constant for temperature increase,
the top line figures [C] and [D] would increase in number and the boHom-line figures [A] and
[B] would have to decrease in number.
If the temperature was decreased, this would also affect the posi1on of the equilibrium and
would cause it to move towards the direc1on of the exothermic reac1on, this would cause
the equilibrium to move to the leW. Decreasing the temperature would make it easier for a
reverse reac1on to occur. A decrease in temperature would also cause the equilibrium
constant (Kc) to decrease in value. If I was to work out the equilibrium constant for
2
C: Inves1gate chemical equilibrium in order to understand the extent to which reac1ons go
to comple1on
1
, What is an equilibrium?
When a chemical reac1on reaches an equilibrium the reactants and their concentra1on
remain the same, this would mean that products would not change and would also remain
the same. Both the forward and backward reac1on have not ceased to con1nue but are
going on at the exact rate of one another. In summary, the rate of a forward reac1on is
equivalent to the rate of a reverse reac1on.
rate vs 1me graphs are a great way to depict no change in reactants or products in an
equilibrium. This could be said the same for concentra1on vs 1me graphs where different
concentra1ons of a reactant can s1ll lead to an equilibrium.
hHp://www.dynamicscience.com.au/tester/solu1ons1/chemistry/equilibrium/Lesson%203-
%20equilibriumgraphs.pdf
How do certain factors affect the posi9on of an equilibrium and the effect of Kc?
Increase/decrease in temperature
The formula/expression for equilibrium constant is as follows:
[C ]c [D]d
Kc =
[A]a [B]b
Temperature is the only factor that affects the value of equilibrium constant (Kc). If the
temperature is increased, this would affect the posi1on of the equilibrium and would move
towards the direc1on of the endothermic reac1on, this would cause the equilibrium to
move to the right. Increasing the temperature of a reac1on causes the equilibrium constant
(Kc) to go up in value. If I was to work out the equilibrium constant for temperature increase,
the top line figures [C] and [D] would increase in number and the boHom-line figures [A] and
[B] would have to decrease in number.
If the temperature was decreased, this would also affect the posi1on of the equilibrium and
would cause it to move towards the direc1on of the exothermic reac1on, this would cause
the equilibrium to move to the leW. Decreasing the temperature would make it easier for a
reverse reac1on to occur. A decrease in temperature would also cause the equilibrium
constant (Kc) to decrease in value. If I was to work out the equilibrium constant for
2
