Chem 1311 Exam 5 ACC Professor Rahman Questions With Complete Solutions

According to VSEPR theory, if there are 2 electron domains on a central atom, they will be arranged such that the angles between the domains are __________. -120° -180° -90° -109.5° -360° correct answer: 180° An electron domain consists of __________. a) a nonbonding pair of electrons b) a single bond c) a multiple bond -a only -b only -c only -a, b, and c -b and c correct answer: a, b, and c The O-C-O bond angle in the CO₃²⁻ ion is approximately __________. -109.5° -120° -60° -180° -90° correct answer: 120° The hybridization of the terminal carbons in the H₂C=C=CH₂ molecule is __________. -sp³d -sp³d² -sp² -sp³ -sp correct answer: sp² Based on molecular orbital theory, the bond order of the C-C bond in the C₂ molecule is __________. -0 -1 -2 -3 -4 correct answer: 2 For which of the molecules is the molecular geometry (shape) the same as the VSEPR electron domain arrangement (electron domain geometry)? (i) PCl₃ (ii) CCl₄ (iii) TeCl₄ (iv) XeF₄ (v) SF₆ -(i) and (ii) -(i) and (iii) -(ii) and (v) -(iv) and (v) -(v) only correct answer: (ii) and (v) The hybridizations of nitrogen in NF₃ and NH₃ are __________ and __________, respectively. -sp³, sp³ -sp², sp² -sp, sp³ -sp³, sp -sp², sp³ correct answer: sp³, sp³ The central Xe atom in the XeF₄ molecule has __________ unbonded electron pairs and __________ bonded pairs in its valence shell. -4, 2 -2, 4 -4, 0 -4, 1 -1, 4 correct answer: 2, 4 The more effectively two atomic orbitals overlap, _______________. -the lower will be the energy of the resulting bonding MO and the higher will be the energy of the resulting antibonding MO. -the higher will be the energies of both bonding and antibonding MOs that result. -the fewer antibonding MOs will be produced by the combination. -the higher will be the energy of the resulting bonding MO and the lower will be the energy of the resulting antibonding MO. -the more bonding MOs will be produced by the combination. correct answer: the lower will be the energy of the resulting bonding MO and the higher will be the energy of the resulting antibonding MO.