Calculate how much glucose (C6H12O6) you would need to make a 0.5 Liter solution which is
0.3 molar. ?
Solution
Molarity(M) = moles of solute / volume of solution
volume = 0.5l
let x gms of glucose be needed
moles of glucose = x / 180 (molecular weight = 180)
M= x/180/0.5
0.3=0.5x/180
0.5x=54
x = 54/0.5
= 108gms
glucose required = 108gms
0.3 molar. ?
Solution
Molarity(M) = moles of solute / volume of solution
volume = 0.5l
let x gms of glucose be needed
moles of glucose = x / 180 (molecular weight = 180)
M= x/180/0.5
0.3=0.5x/180
0.5x=54
x = 54/0.5
= 108gms
glucose required = 108gms
