How much heat is required to melt 15 grams of ice at 0C How much h

How much heat is required to melt 15 grams of ice at 0C? How much heat is released when 100 grams of steam condenses at 100C? If a system of ice and water has a mass of 12 grams, and it is converted completely to water at 0.0C by supplying 1.33 kJ of heat, how much water was initially present? Heat of fusion of ice = 333 J/g Heat of vaporization of water = 2250 J/g Is there a formula to help solve these problems? Solution change the number plz 1. The heat of fusion of water is 333 J/g To melt 68 g needs 68*333 = 22.6 kJ 2. The specific heat capacity of wateris 4.18 J/g-ºK: to melt the iceneeds 333*110 J and to raise the temp of 110 g from 0º to 50º need 110*4.18*50 so the total is 110*(333 + 4.18*50) = 59.6 kJ 3. The heat of vaporization of water is 2257 J/g so to vaporize 26 g needs 2257*26 = 58.7 kJ 4. Since the block is large, it will not melt away and the final temperature in the water will be 0º C The heat needed to reduce 15 g of water from 60 ºC to 0 ºC is 4.18*15*60 = 3762 J Each gram of ice that melts provides 333 J, so the grams of ice that melt are 3762/333 = 11.3 g