Find the x and y intercepts of the line whose equation is:3x-2y=12
Solution
3x - 2y = 12.
-2y = - 3x + 12.
dividing by 2 the whole equation to seperate the y.
y = (3/2)x - 6. y intercept = - 6.
so y intercept is y = -6
to find the x-intercept consider the equation again.
3x = 2y + 12
divide y 3 the whole equation to seperate the x.
x = (2/3)y + 4. x intercept = + 4
so x intercept is x = +4
Solution
3x - 2y = 12.
-2y = - 3x + 12.
dividing by 2 the whole equation to seperate the y.
y = (3/2)x - 6. y intercept = - 6.
so y intercept is y = -6
to find the x-intercept consider the equation again.
3x = 2y + 12
divide y 3 the whole equation to seperate the x.
x = (2/3)y + 4. x intercept = + 4
so x intercept is x = +4
