, Question 1
According to the solubility rules, which of the following compounds will be soluble in
water?
[1] Silver bromide.
[2] Calcium sulfate.
[3] Magnesium fluoride.
[4] Lead sulfate.
[5] Lithium nitrate.
Question 2
Consider an acid-base reaction when hydrochloric acid is added to copper(II) hydroxide.
What is the net ionic equation for this reaction?
[1] H+(aq) + OH-(aq) → H2O(l)
[2] 2H+(aq) + Cu(OH)2(s) → Cu2+(aq) + 2H2O(l)
[3] 2HCl(aq) +Cu(OH)2(s) → CuCl2(s) + 2H2O(l)
[4] 2H+(aq) + 2Cl-(aq) + Cu2+(aq) + 2OH-(aq) → CuCl2(s) + 2H2O(l)
[5] 2H+(aq) + 2Cl-(aq) + Cu2+(aq) + 2OH-(aq) → Cu2+(aq) + 2Cl-(aq) + 2H2O(l)
Question 3
Consider the following chemical reaction:
CdCl2(aq) + NaOH(aq) → Cd(OH)2 + NaCl
After correctly balancing the reaction above, the coefficient of NaOH will be?
[1] 1
[2] 2
[3] 3
[4] 4
[5] 5
Consider the following balanced redox reaction, and answer Questions 4 - 7
2 PbS (s) + 3O2 (g) → 2PbO (s) + 2SO2 (g)
Question 4
Which species contains an element acting as the reducing agent.
[1] O2
[2] PbO
According to the solubility rules, which of the following compounds will be soluble in
water?
[1] Silver bromide.
[2] Calcium sulfate.
[3] Magnesium fluoride.
[4] Lead sulfate.
[5] Lithium nitrate.
Question 2
Consider an acid-base reaction when hydrochloric acid is added to copper(II) hydroxide.
What is the net ionic equation for this reaction?
[1] H+(aq) + OH-(aq) → H2O(l)
[2] 2H+(aq) + Cu(OH)2(s) → Cu2+(aq) + 2H2O(l)
[3] 2HCl(aq) +Cu(OH)2(s) → CuCl2(s) + 2H2O(l)
[4] 2H+(aq) + 2Cl-(aq) + Cu2+(aq) + 2OH-(aq) → CuCl2(s) + 2H2O(l)
[5] 2H+(aq) + 2Cl-(aq) + Cu2+(aq) + 2OH-(aq) → Cu2+(aq) + 2Cl-(aq) + 2H2O(l)
Question 3
Consider the following chemical reaction:
CdCl2(aq) + NaOH(aq) → Cd(OH)2 + NaCl
After correctly balancing the reaction above, the coefficient of NaOH will be?
[1] 1
[2] 2
[3] 3
[4] 4
[5] 5
Consider the following balanced redox reaction, and answer Questions 4 - 7
2 PbS (s) + 3O2 (g) → 2PbO (s) + 2SO2 (g)
Question 4
Which species contains an element acting as the reducing agent.
[1] O2
[2] PbO