BIOCHEM C785 pre assessment #3
What is the complementary sequence to 3’ CAG TAA CAA 5’?Required
to answer. Single choice.
(1/1 Point)
5' TTG TTA CTG 3
3’ GTC ATT GTT 5’
3’ GTT ATT GTC 5’
3' TTG TTA CTG 5
The correct answer is 3' TTG TTA CTG 5'. Remember complementary means “Matching or
Pairing” You have to remember to pay attention to your numbers as well as your letters (A-T,
G- C, 5'-3'). The correct answer is 3’ CAG TAA CAA 5’ (original sequence) 5’ GTC ATT GTT
3’ (complementary sequence) But we asked for it in the 3’ direction, so mirror answer to give
correct answer: 3’ TTG TTA CTG 5’
Correct answers: 3' TTG TTA CTG 5
22,
Which amino acid sequence would result from this Coding DNA strand? 3’ TAC
GTT AAC 5’?Required to answer. Single choice.
(1/1 Point)
Gln Leu His
The correct answer is Gln Leu His. We are starting at the coding strand, and have to remember
the relationship between coding DNA and mRNA. These two strands are non-complementary
and parallel. So we copy the coding strand , change T ---> U, and then write the mRNA
sequence: 3’ TAC GTT AAC 5’ coding 3’ UAC GUU AAC 5’ mRNA Mirror by changing
, BIOCHEM C785 pre assessment #3
orientation: 5’ CAA UUG CAU 3’ Read chart Gln Leu His (chart is in direction of 5' ---> 3') If
you chose Met Gln Leu, this answer is incorrect because this is the amino acid sequence that
results from the mRNA 5' AUG CAA UUG 3' which would have been complementary to the
given coding strand. Coding DNA is non-complementary and parallel to mRNA.
Met Gln Leu
Ile Asp Val
Gln Ile Met
Correct answers: Gln Leu His
33,
Which amino acid sequence would be made from this template DNA
strand? 5’ AGT TAT AAC 3’?Required to answer. Single choice.
(0/1 Point)
Met Leu Thr
Val Ile Thr
Ser Tyr Asn
The correct answer is Val Ile Thr because 5’ AGT TAT AAC 3’ template is complementary
and antiparallel so 3’ UCA AUA UUG 5’ but it is in the wrong orientation, so mirror 5’ GUU
AUA ACU 3’ and read the chart Val Ile Thr
Gln Tyr
Your answer to question 3 is wrong. Correct answers: Val Ile Thr
44,
, BIOCHEM C785 pre assessment #3
Which ingredients/molecules are required to set up a polymerase chain
reaction? Select all that apply.Required to answer. Multiple choice.
(1/1 Point)
Amino Acids
RNA nucleotides
DNA polymerase
Correct! In PCR, a DNA sample is separated into single strands and incubated with DNA
polymerase, deoxynucleotides (dNTPs), and two short DNA primers whose sequences flank the
DNA segment of interest and thus define the region to be amplified. Recall from the section on
DNA replication that DNA polymerase needs a primer to begin DNA synthesis. This requirement
means the primers will direct the DNA polymerase to only synthesize complementary strands of
the target DNA.
DNA nucleotides
Correct! In PCR, a DNA sample is separated into single strands and incubated with DNA
polymerase, deoxynucleotides (dNTPs), and two short DNA primers whose sequences flank the
DNA segment of interest and thus define the region to be amplified. Recall from the section on
DNA replication that DNA polymerase needs a primer to begin DNA synthesis. This requirement
means the primers will direct the DNA polymerase to only synthesize complementary strands of
the target DNA.
Template DNA
Correct! In PCR, a DNA sample is separated into single strands and incubated with DNA
polymerase, deoxynucleotides (dNTPs), and two short DNA primers whose sequences flank the
DNA segment of interest and thus define the region to be amplified. Recall from the section on
DNA replication that DNA polymerase needs a primer to begin DNA synthesis. This requirement
means the primers will direct the DNA polymerase to only synthesize complementary strands of
the target DNA.
DNA Primers
Correct! In PCR, a DNA sample is separated into single strands and incubated with DNA
polymerase, deoxynucleotides (dNTPs), and two short DNA primers whose sequences flank the
DNA segment of interest and thus define the region to be amplified. Recall from the section on
DNA replication that DNA polymerase needs a primer to begin DNA synthesis. This requirement
means the primers will direct the DNA polymerase to only synthesize complementary strands of
the target DNA.
Ribosomes
RNA Primers
Correct answers: DNA polymerase,DNA nucleotides,Template DNA,DNA Primers
55,
Assuming 100% reaction efficiency, how many DNA copies will be produced
after 5 PCR cycles, if we begin with 1 DNA template?Required to answer. Single
choice.
(1/1 Point)
16
8
32
The correct answer is 32. 2x2x2x2x2=32
10
, BIOCHEM C785 pre assessment #3
Correct answers: 32
66,
Which of the following would represent a silent mutation if this is the original
sequence: 5’ UAC AGC CAU 3’?Required to answer. Single choice.
(1/1 Point)
5’ UAG AGC CAU 3’
5' UAC AGC CAU 3'
5’ UAC AGC CAC 3’
Correct! The correct answer is 5' UAC AGC CAC 3', which also gives Tyr Ser His
5’ UAC AGC CAA 3’
Correct answers: 5’ UAC AGC CAC 3’
77,
If the original coding sequence is 5’ CTA TGA GGA TTA 3’ and it is mutated to 5'
CTA TGA CGA TTA 3', what type of mutation would have taken place?Required
to answer. Single choice.
(1/1 Point)
What is the complementary sequence to 3’ CAG TAA CAA 5’?Required
to answer. Single choice.
(1/1 Point)
5' TTG TTA CTG 3
3’ GTC ATT GTT 5’
3’ GTT ATT GTC 5’
3' TTG TTA CTG 5
The correct answer is 3' TTG TTA CTG 5'. Remember complementary means “Matching or
Pairing” You have to remember to pay attention to your numbers as well as your letters (A-T,
G- C, 5'-3'). The correct answer is 3’ CAG TAA CAA 5’ (original sequence) 5’ GTC ATT GTT
3’ (complementary sequence) But we asked for it in the 3’ direction, so mirror answer to give
correct answer: 3’ TTG TTA CTG 5’
Correct answers: 3' TTG TTA CTG 5
22,
Which amino acid sequence would result from this Coding DNA strand? 3’ TAC
GTT AAC 5’?Required to answer. Single choice.
(1/1 Point)
Gln Leu His
The correct answer is Gln Leu His. We are starting at the coding strand, and have to remember
the relationship between coding DNA and mRNA. These two strands are non-complementary
and parallel. So we copy the coding strand , change T ---> U, and then write the mRNA
sequence: 3’ TAC GTT AAC 5’ coding 3’ UAC GUU AAC 5’ mRNA Mirror by changing
, BIOCHEM C785 pre assessment #3
orientation: 5’ CAA UUG CAU 3’ Read chart Gln Leu His (chart is in direction of 5' ---> 3') If
you chose Met Gln Leu, this answer is incorrect because this is the amino acid sequence that
results from the mRNA 5' AUG CAA UUG 3' which would have been complementary to the
given coding strand. Coding DNA is non-complementary and parallel to mRNA.
Met Gln Leu
Ile Asp Val
Gln Ile Met
Correct answers: Gln Leu His
33,
Which amino acid sequence would be made from this template DNA
strand? 5’ AGT TAT AAC 3’?Required to answer. Single choice.
(0/1 Point)
Met Leu Thr
Val Ile Thr
Ser Tyr Asn
The correct answer is Val Ile Thr because 5’ AGT TAT AAC 3’ template is complementary
and antiparallel so 3’ UCA AUA UUG 5’ but it is in the wrong orientation, so mirror 5’ GUU
AUA ACU 3’ and read the chart Val Ile Thr
Gln Tyr
Your answer to question 3 is wrong. Correct answers: Val Ile Thr
44,
, BIOCHEM C785 pre assessment #3
Which ingredients/molecules are required to set up a polymerase chain
reaction? Select all that apply.Required to answer. Multiple choice.
(1/1 Point)
Amino Acids
RNA nucleotides
DNA polymerase
Correct! In PCR, a DNA sample is separated into single strands and incubated with DNA
polymerase, deoxynucleotides (dNTPs), and two short DNA primers whose sequences flank the
DNA segment of interest and thus define the region to be amplified. Recall from the section on
DNA replication that DNA polymerase needs a primer to begin DNA synthesis. This requirement
means the primers will direct the DNA polymerase to only synthesize complementary strands of
the target DNA.
DNA nucleotides
Correct! In PCR, a DNA sample is separated into single strands and incubated with DNA
polymerase, deoxynucleotides (dNTPs), and two short DNA primers whose sequences flank the
DNA segment of interest and thus define the region to be amplified. Recall from the section on
DNA replication that DNA polymerase needs a primer to begin DNA synthesis. This requirement
means the primers will direct the DNA polymerase to only synthesize complementary strands of
the target DNA.
Template DNA
Correct! In PCR, a DNA sample is separated into single strands and incubated with DNA
polymerase, deoxynucleotides (dNTPs), and two short DNA primers whose sequences flank the
DNA segment of interest and thus define the region to be amplified. Recall from the section on
DNA replication that DNA polymerase needs a primer to begin DNA synthesis. This requirement
means the primers will direct the DNA polymerase to only synthesize complementary strands of
the target DNA.
DNA Primers
Correct! In PCR, a DNA sample is separated into single strands and incubated with DNA
polymerase, deoxynucleotides (dNTPs), and two short DNA primers whose sequences flank the
DNA segment of interest and thus define the region to be amplified. Recall from the section on
DNA replication that DNA polymerase needs a primer to begin DNA synthesis. This requirement
means the primers will direct the DNA polymerase to only synthesize complementary strands of
the target DNA.
Ribosomes
RNA Primers
Correct answers: DNA polymerase,DNA nucleotides,Template DNA,DNA Primers
55,
Assuming 100% reaction efficiency, how many DNA copies will be produced
after 5 PCR cycles, if we begin with 1 DNA template?Required to answer. Single
choice.
(1/1 Point)
16
8
32
The correct answer is 32. 2x2x2x2x2=32
10
, BIOCHEM C785 pre assessment #3
Correct answers: 32
66,
Which of the following would represent a silent mutation if this is the original
sequence: 5’ UAC AGC CAU 3’?Required to answer. Single choice.
(1/1 Point)
5’ UAG AGC CAU 3’
5' UAC AGC CAU 3'
5’ UAC AGC CAC 3’
Correct! The correct answer is 5' UAC AGC CAC 3', which also gives Tyr Ser His
5’ UAC AGC CAA 3’
Correct answers: 5’ UAC AGC CAC 3’
77,
If the original coding sequence is 5’ CTA TGA GGA TTA 3’ and it is mutated to 5'
CTA TGA CGA TTA 3', what type of mutation would have taken place?Required
to answer. Single choice.
(1/1 Point)
