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mathematics paper1 memo

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past paper memo for p1 mathematics

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NATIONAL
SENIOR CERTIFICATE/
NASIONALE SENIOR
SERTIFIKAAT



GRADE 12/GRAAD 12



MATHEMATICS P1/WISKUNDE V1

NOVEMBER 2021

MARKING GUIDELINES/NASIENRIGLYNE


MARKS/PUNTE: 150




These marking guidelines consist of 16 pages.
Hierdie nasienriglyne bestaan uit 16 bladsye.




Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

,Mathematics P1/Wiskunde V1 2 DBE/November 2021
NSC/NSS – Marking Guidelines/Nasienriglyne



NOTE:
 If a candidate answers a question TWICE, only mark the FIRST attempt.
 Consistent accuracy applies in all aspects of the marking guidelines.

LET WEL:
 Indien 'n kandidaat 'n vraag TWEE keer beantwoord, sien slegs die EERSTE poging na.
 Volgehoue akkuraatheid is op ALLE aspekte van die nasienriglyne van toepassing.

QUESTION/VRAAG 1
1.1.1 x 2  2 x  24  0
x  6x  4  0 factors
x  6 or x  4 x = 6
x = – 4
(3)
1.1.2 2 x  3x  3  0
2


3  (3) 2  4(2)(3)
x substitution into the correct
2(2) formula
3  33
x
4
x  2,19 or x  0,69 x = 2,19 x = – 0,69
(3)
1.1.3 x  5x  4
2


x 2  5x  4  0  standard form
x  4x  1  0
 critical values
Critical values: x  4 or x  1


+ – +
–4 –1
 4  x  1 OR/OF x  [–4 ; –1] answer
(4)
1.1.4 x  28  2  x
 
x  28  2  x 
2 2
 squaring both sides
x  28  4  4 x  x 2
x 2  5x  24  0  standard form
( x  8)( x  3)  0  factors
x 8 or x  3  answers with selection
(4)




Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

, Mathematics P1/Wiskunde V1 3 DBE/November 2021
NSC/NSS – Marking Guidelines/Nasienriglyne


1.2 2y  3  x
x  2y  3 … (1) equation 1
2 xy  7  x  4 y … (2)
2 2


2 y2 y  3  7  2 y  3  4 y 2
2
substitution
4 y 2  6 y  7  4 y 2  12 y  9  4 y 2 simplification
4y2  6y  2  0
2 y 2  3y 1  0 standard form
2 y  1 y  1  0
1
y  or y  1 y – values
2
x  2 or x  1 x – values
(6)

OR/OF OR/OF

2y  3  x
3 x
y  …(1) equation 1
2 2
2 xy  7  x 2  4 y 2 … (2)
2
3 x 3 x
2 x    7  x 2  4   substitution
2 2 2 2

3x  x 2  7  x 2  9  6 x  x 2 simplification
x 2  3x  2  0 standard form
x  2x  1  0
x  2 or x  1 x – values
1
y  or y  1 y – values
2 (6)
1.3 n p n p
  
m n m n
n 2  mp  n 2  mp
  b 2  4ac
  n 2  4mp , but n 2  mp
  n 2  4n 2 OR/OF   mp  4mp    3n 2 or –3mp
  3n 2
  3mp
n 0
2
mp  0
3n  02
3mp  0

   0  x is a non-real number   0
(4)

[24]


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