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Exam (elaborations)

Engineering Economy, 9th Edition – Leland Blank & Anthony Tarquin – Solutions Manual for Chapters 1–19

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This document contains detailed solutions to the end-of-chapter problems from Engineering Economy, 7th Edition by Leland Blank and Anthony Tarquin. It covers foundational concepts such as cash flow analysis, time value of money, interest rates, present and future worth, gradients, nominal and effective rates, and spreadsheet-based economic analysis across multiple chapters. The material is suitable as a complete solutions reference for students preparing for exams, homework, and in-depth understanding of engineering economy problem-solving methods.

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Engineering Economy, 9th Edition
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Engineering Economy, 9th Edition











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Institution
Engineering Economy, 9th Edition
Course
Engineering Economy, 9th Edition

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Uploaded on
January 16, 2026
Number of pages
351
Written in
2025/2026
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Exam (elaborations)
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Solutions To End-Of-Chapter
Problems Engineering Economy, 7th
Edition Leland Blank And Anthony Tarquin

Chapter 1
Foundations Of Engineering Economy
1.1 The Four Elements Are Cash Flows, Time Of Occurrence Of Cash Flows, Interest
Rates, And Measure Of Economic Worth.

1.2 (A) Capital Funds Are Money Used To Finance Projects. It Is Usually Limited In The
Amount Of Money Available.

(B) Sensitivity Analysis Is A Procedure That Involves Changing Various Estimates To See
If/How They Affect The Economic Decision.

1.3 Any Of The Following Are Measures Of Worth: Present Worth, Future Worth, Annual
Worth, Rate Of Return, Benefit/Cost Ratio, Capitalized Cost, Payback Period, Economic
Value Added.

1.4 First Cost: Economic; Leadership: Non-Economic; Taxes: Economic; Salvage Value:
Economic; Morale: Non-Economic; Dependability: Non-Economic; Inflation: Economic;
Profit: Economic; Acceptance: Non-Economic; Ethics: Non-Economic; Interest Rate:
Economic.

1.5 Many Sections Could Be Identified. Some Are: I.B; II.2.A And B; III.9.A And B.

1.6 Example Actions Are:
 Try To Talk Them Out Of Doing It Now, Explaining It Is Stealing
 Try To Get Them To Pay For Their Drinks
 Pay For All The Drinks Himself
 Walk Away And Not Associate With Them Again

1.7 This Is Structured To Be A Discussion Question; Many Responses Are Acceptable. It Is An
Ethical Question, But Also A Guilt-Related Situation. He Can Justify The Result As An
Accident; He Can Feel Justified By The Legal Fault And Punishment He Receives; He Can
Get Angry Because It WAS An Accident; He Can Become Tormented Over Time Due To
The Stress Caused By Accidently Causing A Child’s Death.

1.8 This Is Structured To Be A Discussion Question; Many Responses Are Acceptable.
Responses Can Vary From The Ethical (Stating The Truth And Accepting The
Consequences) To Unethical (Continuing To Deceive Himself And The Instructor And
Devise Some On-The-Spot Excuse).

Lessons Can Be Learned From The Experience. A Few Of Them Are:
 Think Before He Cheats Again.
1

,  Think About The Longer-Term Consequences Of Unethical Decisions.
 Face Ethical-Dilemma Situations Honestly And Make Better Decisions In Real Time.
Alternatively, Claude May Learn Nothing From The Experience And Continue His
Unethical Practices.

1.9 I = [(3,885,000 - 3,500,000)/3,500,000]*100% = 11% Per Year

1.10 (A) Amount Paid First Four Years = 900,000(0.12) = $108,000

(B) Final Payment = 900,000 + 900,000(0.12) = $1,008,000

1.11 I = (1125/12,500)*100 = 9%
I = (6160/56,000)*100 = 11%
I = (7600/95,000)*100 = 8%

The $56,000 Investment Has The Highest Rate Of Return.

1.12 Interest On Loan = 23,800(0.10) =
$2,380 Default Insurance = 23,800(0.05)
= $1190
Set-Up Fee = $300

Total Amount Paid = 2380 + 1190 + 300 = $3870

Effective Interest Rate = (3870/23,800)*100 = 16.3%

1.13 The Market Interest Rate Is Usually 3 – 4 % Above The Expected Inflation Rate.

Therefore, Market Rate Is In The Range 3 + 8 To 4 + 8 = 11 To 12% Per Year

1.14 PW = Present Worth; PV = Present Value; NPV = Net Present Value; DCF = Discounted
Cash Flow; And CC = Capitalized Cost

1.15 P = $150,000; F = ?; I = 11%; n= 7

1.16 P = ?; F = $100,000; I = 12%; n = 2

1.17 P = $3.4 Million; A = ?; I = 10%; n = 8

1.18 F = ?; A = $100,000 + $125,000?; I = 15%; n= 3

1.19 End-Of-Period Convention Means That All Cash Flows Are Assumed To Take Place At
The End Of The Interest Period In Which They Occur.

1.20 Fuel Cost: Outflow; Pension Plan Contributions: Outflow; Passenger Fares: Inflow;
Maintenance: Outflow; Freight Revenue: Inflow; Cargo Revenue: Inflow; Extra Bag
Charges: Inflow; Water And Sodas: Outflow; Advertising: Outflow; Landing Fees:
2

, Outflow; Seat Preference Fees: Inflow.
1.21 End-Of-Period Amount For June = 50 + 70 + 120 + 20 =
$260 End-Of-Period Amount For Dec = 150 + 90 + 40 + 110
= $390

1.22 Month Receipts, $1000 Disbursements, $1000 Net CF, $1000
Jan 500 300 +200
Feb 800 500 +300
Mar 200 400 -200
Apr 120 400 -280
May 600 500 +100
June 900 600 +300
July 800 300 +500
Aug 700 300 +400
Sept 900 500 +400
Oct 500 400 +100
Nov 400 400 0
Dec 1800 700 +1100

Net Cash Flow = $2,920 ($2,920,000)

1.23




1.24




3

, 1.25




1.26 Amount Now = F = 100,000 + 100,000(0.15) = $115,000

1.27 Equivalent Present Amount = 1,000,000/(1 + 0.15)
= $869,565

Discount = 790,000 – 869,565
= $79,565

1.28 5000(40 )(1 + i) = 225,000
1 + i = 1.125
i = 0.125 = 12.5% Per Year

1.29 Total Bonus Next Year = 8,000 + 8,000(1.08)
= $16,640

1.30 (A) Early-Bird Payment = 10,000 – 10,000(0.10) = $9000

(b) Equivalent Future Amount = 9000(1 + 0.10) =

$9900 Savings = 10,000 – 9900 = $100

1.31 F1 = 1,000,000 + 1,000,000(0.10)
= 1,100,000

F2 = 1,100,000 + 1,100,000(0.10)
= $1,210,000

1.32 90,000 = 60,000 + 60,000(5)(I)
300,000 i = 30,000
Ii= 0.10 (10% Per Year)

1.33 (A) F = 1,800,000(1 + 0.10) (1 + 0.10) = $2,178,000

(b) Interest = 2,178,000 – 1,800,000 = $378,000



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