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WGU D335 PRACTICE TEST 2 | PRACTICE QUESTIONS WITH ANSWERS FOR PA | 2025/2026 UPDATE | 100% CORRECT!!

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WGU D335 PRACTICE TEST 2 | PRACTICE QUESTIONS WITH ANSWERS FOR PA | 2025/2026 UPDATE | 100% CORRECT!!












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December 25, 2025
Number of pages
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Written in
2025/2026
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WGU D335 PRACTICE TEST 2 | PRACTICE
QUESTIONS WITH ANSWERS FOR PA |
2025/2026 UPDATE | 100% CORRECT!!




1 of 15

Term


Create a solution that accepts an integer input representing
the index value for any any of the five elements in the
following list: various_data_types = [516, 112.49, True, "meow",
("Western", "Governors", "University"), {"apple": 1, "pear": 5}]
Using the built-in function type() and getting its name by
using the
.name attribute, output data type (e.g., int”, “float”, “bool”,
“str”) based on the input index value of the list element.



Give this one a try later!

,b1 =
int(input()) b2
= int(input())
h =
int(input())
area_value = ((b1 + b2) /2) * h
print('Trapezoid area: {:.1f} square meters'.format(area_value))



file_name = input()
with open(file_name, 'r') as f:
word1 =
str(f.readline()).strip()
word2 =
str(f.readline()).strip()
word3 =
str(f.readline()).strip()

f = open(file_name,
'r') lines =
f.read().splitlines()
lines = ' '.join(lines)
f.close()
print(f'{word1}\n{word2}\n{word3}\n{lines}')




index_value =
int(input()) try:
if index_value ==
0:
print(frameworks[
0]) if index_value
== 1:
print(frameworks[
1]) if index_value
== 2:
print(frameworks[
2]) if index_value
== 3:
print(frameworks[
3]) if index_value
== 4:
print(frameworks[
4]) if index_value
== 5:
print(frameworks[

,5]) if index_value
> 5:
print(frameworks[index_value])
except:
print('Error')




index_value = int(input())
name = various_data_types[index_value]

, data_type = type(name).__name__
print(f"Element {index_value}:
{data_type}")

Don't know?




2 of 15

Definition



num1 =
int(input()) num2
= int(input())
num3 =
int(input()) num4
= int(input())
num5 =
int(input())
first_output = num1 + num2 + num3 + num4 + num5
second_output = float(num1) + float(num2) + float(num3) +
float(num4)
+ float(num5)
third_output = str(num1) + str(num2) + str(num3) + str(num4) +
str(num5)
print('Integer:
{}'.format(first_output)) print('Float:
{}'.format(second_output))
print('String:
{}'.format(third_output))



Give this one a try later!



Create a solution that accepts five integer inputs. Output the
sum of the five inputs three times, converting the inputs to the
requested data type prior to finding the sum.

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