DAT FL #10 GChem Questions with complete solution
2025/2026
1. What is the
(5)(0.082)(300)/(15)
pres- sure of an
ideal gas if 5.0 PV=nRT
mol occupies a P=nRT/V
volume of 15.0 L 5 mol * 0.0821 *
at 300 K?
*0.0821 used for pressure in
atmospheres CH4
2. In which of the
fol- lowing
CH4 is nonpolar therefore it only displays London dispersion forces
substances is
dispersion like-
ly to be the
most
important factor in The boiling point of small molecules depends on the strength of the
intermol-
determining solu- tion B?
boil- ing point?
4. If two moles of C2H2 reacts with 96 g of
3. Solution A is O2 in
found to have a
high-
er vapor
pressure than
solution B.
Based on this
find- ing, which
of the following
conclu- sions
can be made
about solution A
compared to
1/
19
,ecular interactions. A solution with a higher vapor pressure will have weaker intermolecular
Both polar and nonpolar forces
and boiling point, allowing the molecules to easily escape into the
molecules contain gaseous phase
London dispersion
forces. Solution A has a
lower boiling point and
weaker intermolecular 1.2 mol
forces 96 g O2 x (1 mol O2/32 g O2) = 3 mol O2
a combustion reac-
2CH2CH2 + 5O2 -> 4CO2 + 2H2O
tion, what is
the
2/
19
, DAT FL #10 GChem
Study online at
https://quizlet.com/_fcbuk4
theoretical yield of*for every 2 moles of C2H2 5 moles of
H2O? O2 are needed
2C2H2 + 5O2 ’4CO2 need 5 mols of O2
but
+ only have 3 mols
2H2O
3 mol O2 x (2 mol H2O/5 mol O2) =
1.2 mol H2O
OR
2/5 = 4/10 = 0.4
3x0.4 = 1.2
5. Determine the rate rate = k[NO]^2[H2]
law for the reaction
from the 1. look for where NO is changed and H2 remains the same
following data: -trials 1 and 3
2 NO + 2 H2 ’N2 2. divide larger concentration by smaller concentration
+ H2O - 1.0/0.5= 2
3. do the same thing with the rates
- 6.0x10^-2/1.5*10^-2 = 4
4. set up
equation 2^x
=4
x=2
5. look for where H2 changed and NO remains the same
-trials 1 and 2
6. divide larger concentration by smaller
concentration 0.5/0.25 = 2
7. do the same thing with the
3/
19
2025/2026
1. What is the
(5)(0.082)(300)/(15)
pres- sure of an
ideal gas if 5.0 PV=nRT
mol occupies a P=nRT/V
volume of 15.0 L 5 mol * 0.0821 *
at 300 K?
*0.0821 used for pressure in
atmospheres CH4
2. In which of the
fol- lowing
CH4 is nonpolar therefore it only displays London dispersion forces
substances is
dispersion like-
ly to be the
most
important factor in The boiling point of small molecules depends on the strength of the
intermol-
determining solu- tion B?
boil- ing point?
4. If two moles of C2H2 reacts with 96 g of
3. Solution A is O2 in
found to have a
high-
er vapor
pressure than
solution B.
Based on this
find- ing, which
of the following
conclu- sions
can be made
about solution A
compared to
1/
19
,ecular interactions. A solution with a higher vapor pressure will have weaker intermolecular
Both polar and nonpolar forces
and boiling point, allowing the molecules to easily escape into the
molecules contain gaseous phase
London dispersion
forces. Solution A has a
lower boiling point and
weaker intermolecular 1.2 mol
forces 96 g O2 x (1 mol O2/32 g O2) = 3 mol O2
a combustion reac-
2CH2CH2 + 5O2 -> 4CO2 + 2H2O
tion, what is
the
2/
19
, DAT FL #10 GChem
Study online at
https://quizlet.com/_fcbuk4
theoretical yield of*for every 2 moles of C2H2 5 moles of
H2O? O2 are needed
2C2H2 + 5O2 ’4CO2 need 5 mols of O2
but
+ only have 3 mols
2H2O
3 mol O2 x (2 mol H2O/5 mol O2) =
1.2 mol H2O
OR
2/5 = 4/10 = 0.4
3x0.4 = 1.2
5. Determine the rate rate = k[NO]^2[H2]
law for the reaction
from the 1. look for where NO is changed and H2 remains the same
following data: -trials 1 and 3
2 NO + 2 H2 ’N2 2. divide larger concentration by smaller concentration
+ H2O - 1.0/0.5= 2
3. do the same thing with the rates
- 6.0x10^-2/1.5*10^-2 = 4
4. set up
equation 2^x
=4
x=2
5. look for where H2 changed and NO remains the same
-trials 1 and 2
6. divide larger concentration by smaller
concentration 0.5/0.25 = 2
7. do the same thing with the
3/
19
