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PASS | BONE DENSITOMETRY EXAM
[BRAND NEW]
Bone densitometry is what kind of technique?
Quantitative
Statistical variance is:
The average of the squared differences from the mean
the square root of the sample mean multiplied by the difference between individual
samples
the square of the sample values multiplied by the sample mean
the square root of the sum of all the sample values
The average of the squared differences from the mean
Standard deviation is:
,the square root of the sum of all the sample values
the square of the sample values multiplied by the sample mean
The square root of the variance
the square root of the sample mean multiplied by the difference between individual
samples
The square root of the variance
Calculate the standard deviation from the sample population below:
(HINT - remember you are working with a sample population)
5
7
4
9
3
5
7
4
9
2
2.42
Which of the following standard scores is used to compare a patient's BMD to the
average peak value for a young adult of the same sex?
T - Score
,Y - Score
Z - Score
Average BMC
T - Score
Which of the following standard scores is used to compare a patient's BMD to the
average value for the same age and sex as the patient?
Z - Score
Average BMC
Y - Score
T - Score
Z - Score
How would the following bone densitometry standardized scores be interpreted:
L1 T-score -2.6
L1 Z-score -1.4
The bone density of the patient's first lumbar vertebra has a variance of 2.6 grams
below the value predicted for the patient's age and 1.4 grams below the peak
average for a young adult.
The bone density of the patient's first lumbar vertebra is 2.6 standard deviations
below the peak value for a young adult and 1.4 standard deviations below the value
predicted for the patient's age.
The bone density of the patient's first lumbar vertebra has a variance of 2.6 grams
below the peak average for a young adult and 1.4 grams below the value predicted
for the patient's age.
, The bone density of the patient's first lumbar vertebra is 2.6 standard deviations
below the value predicted for the patient's age and 1.4 standard deviations below
the peak value for a young adult.
The bone density of the patient's first lumbar vertebra is 2.6 standard deviations
below the peak value for a young adult and 1.4 standard deviations below the value
predicted for the patient's age.
How would the following bone densitometry standardized scores be interpreted:
L1 T-score 1.7
L1 Z-score -0.8
The bone density of the patient's first lumbar vertebra is 1.7 standard deviations
above the value predicted for the patient's age and 0.8 standard deviations below
the peak value for a young adult.
The bone density of the patient's first lumbar vertebra has a variance of 1.7 grams
above the peak average for a young adult and 0.8 grams below the value predicted
for the patient's age.
The bone density of the patient's first lumbar vertebra is 1.7 standard deviations
above the peak value for a young adult and 0.8 standard deviations below the value
predicted for the patient's age.
The bone density of the patient's first lumbar vertebra has a variance of 1.7 grams
above the value predicted for the patient's age and 0.8 grams below the peak
average for a young adult.
The bone density of the patient's first lumbar vertebra is 1.7 standard deviations
above the peak value for a young adult and 0.8 standard deviations below the value
predicted for the patient's age.
The graph, often in color, in a bone densitometry report is called
Z-score versus T-score comparison graph