12/14/25, 2:48 PM WGU statistics Flashcards | Quizlet
Math Probability
WGU statistics EXAM ACTUAL QUESTIONS AND
CORRECT VERIFIED ANSWERS ALREADY GRADED A+
100% GUARANTEED PASS!
C
Terms in this set (87)
The probability of any event is For any event A, 0 ≤ P(A) ≤ 1.
between one and o. What is the
equation for this?
The sum of all possible One, the equation is :P(S) = 1
probabilities is___?
What is the complement rule? or P(not A) = 1 - P(A)
the probability that an event
does not occur is 1 minus the
probability that it does occur.
In probability, "OR" means either P(A or B) = P(event A occurs or event B occurs or both occur)
one or the other or both.
Two events that cannot occur at disjoint or mutually exclusive
the same time are called
The Addition Rule for Disjoint If A and B are disjoint events, then P(A or B) = P(A) + P(B).
Events:
P(A and B) = P(event A occurs and event B occurs)
is about whether or not it is possible for the events to occur at
The idea of disjoint events is
the same time
whether or not the events affect each other in the sense that the
The idea of independent events
occurrence of one event affects the probability of the
is about
occurrence of the other
If A and B Disjoint A and B can not be indepentdent
If A and B are two independent P(A and B) = P(A) * P(B).
events (Multiplication Rule)
if A, B and C are three P(A and B and C) = P(A) P(B) P(C)
independent events,
The Complement Rule, P(A) = 1 - P(not A),
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, 12/14/25, 2:48 PM WGU statistics Flashcards | Quizlet
P(L) = 1 - P(not L) = 1 - P(not O1 Applying the Multiplication rule:Now, using the multiplication
and not O2 and not O3 and not rule, = 1 - (.56 .56 .56 .56 .56 .56 .56 .56 .56 * .56) = 1 - .003 = .997.
O4 and not O5 and not O6 and
not O7 and not O8 and not O9
and not O10).
P(at least one person chosen P((O and O) or (O and not O) or (not O and O)) = (.44 .44) + (.44
has blood type O) .56) + (.56 * .44) = .6864.
If A and B are disjoint events - P(A and B)= 0
The General Addition Rule states P(A or B) = P(A) + P(B) - P(A and B)
that for any two events,
When each of two outcomes there are four possible combinations altogether, which
has two possible values correspond to the four possible outcomes.
(yes/no),
How do we build a two-way Horizontally, A, not A and total, Vertically, B. not B and total
table of probabilities?
In a two-way table of 1
probabilities, what is the total of
all outcomes (lower right
corner?)
P(B | A) = P(B)
Two events A and B are P(A | B) = P(A)
independent if any one of the
following hold: P(B | A) = P(B | not A)
P(A and B) = P(A) * P(B)
In general, another method for P(A and B) to P(A) * P(B). If the two are equal, then A and B are
checking the independence of independent, otherwise the two are not independent.
events A and B is to compare
"one in every thousand people P(H) = .001
(0.001) of all individuals are
infected with HIV (H) - give
equasion
If someone actually has HIV, the P(T | H) = .95
probability of testing positive is
.95" (H) give equasion
Use the General Multiplication P(H and T) = P(H) * P(T given H) = .001 x .95 = .00095.
Rule to find the probability that
someone chosen at random
from the population has HIV and
tests positive. (H is HIV positive
and probability of HIV+ test
accuracy is .95)
IF person is HIV positive and P(not T | H) = 1 - P(T | H) = 1 - .95 = .05.
test accuracy is .95, what are the
chances that that person will test
negative (give equation)
In a probability tree, the non-conditional probabilities
probabilities in the first branch-
off are
https://quizlet.com/90420809/wgu-statistics-flash-cards/ 2/6
Math Probability
WGU statistics EXAM ACTUAL QUESTIONS AND
CORRECT VERIFIED ANSWERS ALREADY GRADED A+
100% GUARANTEED PASS!
C
Terms in this set (87)
The probability of any event is For any event A, 0 ≤ P(A) ≤ 1.
between one and o. What is the
equation for this?
The sum of all possible One, the equation is :P(S) = 1
probabilities is___?
What is the complement rule? or P(not A) = 1 - P(A)
the probability that an event
does not occur is 1 minus the
probability that it does occur.
In probability, "OR" means either P(A or B) = P(event A occurs or event B occurs or both occur)
one or the other or both.
Two events that cannot occur at disjoint or mutually exclusive
the same time are called
The Addition Rule for Disjoint If A and B are disjoint events, then P(A or B) = P(A) + P(B).
Events:
P(A and B) = P(event A occurs and event B occurs)
is about whether or not it is possible for the events to occur at
The idea of disjoint events is
the same time
whether or not the events affect each other in the sense that the
The idea of independent events
occurrence of one event affects the probability of the
is about
occurrence of the other
If A and B Disjoint A and B can not be indepentdent
If A and B are two independent P(A and B) = P(A) * P(B).
events (Multiplication Rule)
if A, B and C are three P(A and B and C) = P(A) P(B) P(C)
independent events,
The Complement Rule, P(A) = 1 - P(not A),
https://quizlet.com/90420809/wgu-statistics-flash-cards/ 1/6
, 12/14/25, 2:48 PM WGU statistics Flashcards | Quizlet
P(L) = 1 - P(not L) = 1 - P(not O1 Applying the Multiplication rule:Now, using the multiplication
and not O2 and not O3 and not rule, = 1 - (.56 .56 .56 .56 .56 .56 .56 .56 .56 * .56) = 1 - .003 = .997.
O4 and not O5 and not O6 and
not O7 and not O8 and not O9
and not O10).
P(at least one person chosen P((O and O) or (O and not O) or (not O and O)) = (.44 .44) + (.44
has blood type O) .56) + (.56 * .44) = .6864.
If A and B are disjoint events - P(A and B)= 0
The General Addition Rule states P(A or B) = P(A) + P(B) - P(A and B)
that for any two events,
When each of two outcomes there are four possible combinations altogether, which
has two possible values correspond to the four possible outcomes.
(yes/no),
How do we build a two-way Horizontally, A, not A and total, Vertically, B. not B and total
table of probabilities?
In a two-way table of 1
probabilities, what is the total of
all outcomes (lower right
corner?)
P(B | A) = P(B)
Two events A and B are P(A | B) = P(A)
independent if any one of the
following hold: P(B | A) = P(B | not A)
P(A and B) = P(A) * P(B)
In general, another method for P(A and B) to P(A) * P(B). If the two are equal, then A and B are
checking the independence of independent, otherwise the two are not independent.
events A and B is to compare
"one in every thousand people P(H) = .001
(0.001) of all individuals are
infected with HIV (H) - give
equasion
If someone actually has HIV, the P(T | H) = .95
probability of testing positive is
.95" (H) give equasion
Use the General Multiplication P(H and T) = P(H) * P(T given H) = .001 x .95 = .00095.
Rule to find the probability that
someone chosen at random
from the population has HIV and
tests positive. (H is HIV positive
and probability of HIV+ test
accuracy is .95)
IF person is HIV positive and P(not T | H) = 1 - P(T | H) = 1 - .95 = .05.
test accuracy is .95, what are the
chances that that person will test
negative (give equation)
In a probability tree, the non-conditional probabilities
probabilities in the first branch-
off are
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