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C784 - REVIEW TESTS - 4,5,6,7 EXAM QUESTIONS WITH COMPLETE SOLUTIONS

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The correct answer is c. This histogram reveals a distribution that is positively skewed as the long tail of the graph is to the right of the peak. - ANSWERSa) Normal b) Negatively Skewed c) Positively Skewed d) Cannot determine The answer is c. Use the Empirical Rule to determine that 95%95% of the diastolic blood pressure values will be within two standard deviations of the mean. Therefore, the upper limit will be: 65.3+2(11.3)=65.3+22.6=87.965.3+2(11.3)=65.3+22.6=87.9 And the lower limit will be: 65.3−2(11.3)=65.3−22.6=42.765.3-2(11.3)=65.3-22.6=42.7 Therefore, 95%95% of the diastolic blood pressures will be between 42.742.7 mm Hg and 87.987.9 mm Hg. - ANSWERS2)Adult diastolic blood pressures are normally distributed. The mean is 65.3 mm Hg and the standard deviation is 11.3 mm Hg. What values would 95%95% of the data fall between? a) 47.2 and 89.7 b) 42.2 and 86.9 c) 42.7 and 87.9 d) 41.6 and 86.8 The answer is b. The Standard Deviation Rule says that 68% of the values will fall within 11 standard deviation of the mean. - ANSWERS3) Assuming that adult diastolic blood pressures are normally distributed, what is the approximate percentage of adults who have diastolic blood pressures within 11 standard deviation of the mean, or between 54.0mm Hg and 76.6 mm Hg? a) 50% b) 68% c) 95.4%

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C784 - REVIEW TESTS - 4,5,6,7 EXAM
QUESTIONS WITH COMPLETE
SOLUTIONS
The correct answer is c. This histogram reveals a distribution that is positively skewed
as the long tail of the graph is to the right of the peak. - ANSWERSa) Normal
b) Negatively Skewed
c) Positively Skewed
d) Cannot determine

The answer is c. Use the Empirical Rule to determine that 95%95% of the diastolic
blood pressure values will be within two standard deviations of the mean.
Therefore, the upper limit will be:
65.3+2(11.3)=65.3+22.6=87.965.3+2(11.3)=65.3+22.6=87.9
And the lower limit will be:
65.3−2(11.3)=65.3−22.6=42.765.3-2(11.3)=65.3-22.6=42.7
Therefore, 95%95% of the diastolic blood pressures will be between 42.742.7 mm Hg
and 87.987.9 mm Hg. - ANSWERS2)Adult diastolic blood pressures are normally
distributed. The mean is 65.3 mm Hg and the standard deviation is 11.3 mm Hg. What
values would 95%95% of the data fall between?

a) 47.2 and 89.7
b) 42.2 and 86.9
c) 42.7 and 87.9
d) 41.6 and 86.8

The answer is b. The Standard Deviation Rule says that 68% of the values will fall
within 11 standard deviation of the mean. - ANSWERS3) Assuming that adult diastolic
blood pressures are normally distributed, what is the approximate percentage of adults
who have diastolic blood pressures within 11 standard deviation of the mean, or
between 54.0mm Hg and 76.6 mm Hg?
a) 50%
b) 68%
c) 95.4%
d) 99.7%

The answer is d. The range is the difference between the smallest and greatest values
(maximum and minimum) of a data set. The minimum value is 48; the maximum is 84.
84 -48 = 36 - ANSWERS4) What is the range of the following data set?
a) 26
b) 28
c) 32

, d) 36

The answer is a. To find the mean, the first step is to add all of the values together.
Then divide that sum (784) by the number of values in the data set (12) . 78/412=65.3 -
ANSWERS5) What is the mean of the following data set?
a) 65.3
b) 69.2
c) 61.6
d) 64.4

The answer is c. As there are an even number of data points in this data set, the
median is half-way between 125 and 125. Therefore, the second quartile (Q2), also
called the median, =125. - ANSWERS6) What is second quartile (Q2Q2) of this data
set?
a) 123
b) 124
c) 125
d) 125.5

The answer is d. Find the median, or mid-point, of the data set:78 85 87 90 100 105 115
117 123 125 | 125 128 135 140 152 159 160 165 169 17978 85 87 90 100 105 115 117
123 125 | 125 128 135 140 152 159 160 165 169 179To find the first quartile (Q1Q1)
identify the median of the lower half of the data set:78 85 87 90 100 | 105 115 117 123
125 | 125 128 135 140 152 159 160 165 169 17978 85 87 90 100 | 105 115 117 123
125 | 125 128 135 140 152 159 160 165 169 179The median of the lower half of the
data set falls between 100100 and 105105. Therefore the first quartile(Q1Q1)
=(100+105)2=102.5 - ANSWERS7) What is the first quartile (Q1Q1) of this data set?
a) 100
b) 103.5
c) 105
d) 102.5

Correct. The answer is b. Find the median, or mid-point, of the data set:78 85 87 90 100
105 115 117 123 125 | 125 128 135 140 152 159 160 165 169 17978 85 87 90 100 105
115 117 123 125 | 125 128 135 140 152 159 160 165 169 179To find the third quartile
(Q3Q3) identify the median of the upper half of the data set:78 85 87 90 100 105 115
117 123 125 | 125 128 135 140 152 | 159 160 165 169 17978 85 87 90 100 105 115
117 123 125 | 125 128 135 140 152 | 159 160 165 169 179The median of the upper half
of the data set falls between 152152 and 159159. Therefore the third
quartile(Q3Q3)=(152+159)2=155.5=(152+159)2=155.5 - ANSWERS8) What is the third
quartile (Q3) of this data set?
a) 152
b) 155.5
c) 157
d) 159

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